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3 years ago

14

Six hundred people are competing in a triathlon. There is a $1000 prize for first and a $500 prize for second. How many differen

t first-second place finishes are possible?

1 answer:

Free_Kalibri [48]3 years ago

6 0

Answer:

10626

Step-by-step explanation:

The total number of people purchase raffle tickets=23

The total number of prizes = 3

Since , order matters here , so we use Permutations.

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Simplify the expression 18x^2/3x^6 .

sammy [17]

Answer:

6/x^4

Step-by-step explanation:

7 0

3 years ago

I am having trouble with converges and diverges<br>

inna [77]

Answer:

d. converges, -25

Step-by-step explanation:

An infinite geometric series converges if the absolute value of the common ratio is less than 1.

Here, the common ratio is 4/5:

| 4/5 | = 4/5 < 1

So the series converges. The sum of an infinite geometric series is:

S = a₁ / (1 − r)

where a₁ is the first term and r is the common ratio.

Here, a₁ = -5 and r = 4/5:

S = -5 / (1 − 4/5)

S = -25

5 0

3 years ago

#12. How is the answer 48? How do I get it?

VashaNatasha [74]

You do 9+3 which equals 12 then you multiply that by 4

3 0

3 years ago

Read 2 more answers

If your credit card is stolen and the thief runs up a total debt of $1,000, but you notify the issuer of the card as soon as you

Yuki888 [10]

Answer:

50 dollars

Step-by-step explanation:

college website

3 0

2 years ago

Solve 2x^2 + x - 4 = 0 <br> X2 +

damaskus [11]

Answer:

$\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }$

Step-by-step explanation:

Hello, please find below my work.

$2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0$

$\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0

3 years ago