Answer:
The answer is 0.25
Step-by-step explanation:
(1)we group like terms by subtracting 32.50 by 28.75
(2) we subtract 20 and 5 to give us a value of 15
(3)when we subtract 32.50 and 28.75 we get a value of 3.75
(4)so the equation will look like this 3.75t = 15
(5)we divide 3.75 we both the two equations
(6)With a correct calculation, Your answer should be t = 0.25
Answer:
The answer is 10y + 48.
Step-by-step explanation:
First you have to get rid of brackets by expanding :
Next you have to collect like-terms :
We know -48 came from (a)(-6), the "L" in "FOIL".
If -48 = -6a, then a = 8.
Now with a=8, go ahead and FOIL (x+8)(x-6) to find m.
Given that R(ABCDE) is in Boyce-Codd normal form.
And AB is the only key for R.
Definition
A relational nontrivial Schema R is in BCNF if FD (X-A) holds in R, Super key of R. whenever then X is
a
Given that AB is the only key for R.
ABC E (Yes).
check if ABC is a Super key. AB is a key, ABC is A B C E is in BONE a super key.
2) ACE B
(NO). no Check if ACE As there is ACE is not a Super key? AB in Super key. ACE.
ACE B
is
Boyce-Codd Normal Form not in BENE (NO)
3) ACDE → B (NO)
check if is a super key. ACDE
As ACDE there is not any AB Tn ACDE. a super key.
ACDEB is not in BCNF.
4) BS → C → (NO)
As there is no AB in BC ~. B(→ not in BCNF
BC is not a super key.
5) ABDE (Yes).
Since AB is a key.
ABO TS a super key.
.. ABDE → E is in BCNF
Let R(ABCDE) be a relation in Boyce-Codd Normal Form (BCNF). If AB is the only key for R, identify each of these FDs from the following list. Answer Yes or No and explain your answer to receive points.
1. ABC E
2. ACE B
3. ACDE B
4. BC C
5. ABD E
Learn more about Boyce-Codd Normal Form at
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term = previous term + Common difference
-20= -16 + Common difference
Common difference = -20-(-16)= - 4
Common difference = -24-(-20) = -4
Answer is C. -4.
