The sum of the numbers is 20 10+10=20 20/2=10
Properties of Logs
logb(x/y) = log<span>bx</span> - log<span>by</span>.
therefore
log5 (4/7)= log5 (4)- log5 (7)
<span>Solve log 5 (4) and log 5 (7) with the base change of the logarithm</span>
<span>log 5 4 = log 4 / log 5 </span>
Use the calculator:
<span>
<span>log 5 4 =0.8613531161
</span></span>
log 5 7 = log 7 / log 5
<span>log 5 7 =1.2090619551</span>
<span>log5 (4/7)= log5
(4)- log5 (7)=-0.347708839</span>
Answer:
= x
Step-by-step explanation:
In right triangles the sum of square length of two legs is equal to square length of hypotenuse:
7^2 + 8^2 = x^2
49 + 64 = x^2 add like terms
113 = x^2 find the root for both sides
= x
The numbers that have a digit in the ones place that is 1/10 of the value in the tens place are 1,055 and 3,222.
<h3>What digits are in the ones place?</h3>
The ones place refers to the position immediately before the decimal.
The digit in the tens place is the number immediately left of the ones place.
The numbers that have ones digits that are 1/10 of the digits in the tens place that are 1,055 and 3,222.
That is because 5 is 1/10 of the tens value of 50 and 2 is 1/10 of the 20 in the tens place.
Find out more on the positions of digits at brainly.com/question/579274
#SPJ1
<h2>
Question:</h2>
At Priscilla's school, the final grade for her Calculus course is weighted as follows: Tests: 50% Quizzes: 30% Homework: 20% Priscilla has an average of 87% on her tests, 100% on her quizzes, and 20% on her homework. What is Priscilla's weighted average?
<h2>
Work:</h2>
Weighted Average gives weights to each percent of the average as follows:
Weighted Average = Average * weighting percent
Weighted Average = Test Average * Test Weighting + Quiz Average. * Quiz Weighting + Homework Average * Homework Weighting
Weighted Average = 87% * 50% + 100% * 30% + 20% * 20%
Weighted Average = 43.5% + 30% + 4%
Weighted Average = 77.5%
<h2>
Answer:</h2>
77.5%
Learn more:
brainly.com/question/26499519
Graphing
brainly.com/question/26479805
Converting fractions into decimals
Thank You!
Answered by: ms115
