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andrew-mc [135]
3 years ago
15

PLEASE HELP MEEEEEEE

Mathematics
1 answer:
Furkat [3]3 years ago
4 0

25 \sqrt{x}
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Step-by-step explanation:

13  \frac{1}{8}

is the required answer

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2 17/20

Step-by-step explanation:

1 7/10+1 1/2=1 7/10+1 10/20=2 17/20

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NEED HELP WITH A MATH QUESTION
Lady_Fox [76]

Answer:

\dfrac{18}{5}

Step-by-step explanation:

The picture shows three isosceles tirangles with the same legs. The base of each triangle is 12 units, 5x-3 units and 17 units.

Since the angles at vertex of each isosceles triangles are 27°, 28° and 29°, then the lengths of the bases satisfy the double inequality

15<5x-3<17

Add 3 to this inequality

15+3<5x-3+3<17+3

18<5x<20

Divide it by 5:

\dfrac{18}{5}

3 0
3 years ago
5 to the power of two
Maksim231197 [3]

Answer:

25

Step-by-step explanation:

5^2 = 25

5 * 5 = 25

6 0
3 years ago
Read 2 more answers
According to the U.S. Bureau of the Census, the average age of brides marrying for the first time is 23.9 years with a populatio
JulsSmile [24]

Answer:

We conclude that young women are delaying marriage and marrying at a later age.

Step-by-step explanation:

We are given that the average age of brides marrying for the first time is 23.9 years with a population standard deviation of 4.2 years.

The sociologist randomly samples 100 marriage records and determines the average age of the first time brides is 24.9 years.

Let \mu = <u><em>average age of brides marrying for the first time.</em></u>

So, Null Hypothesis, H_0 : \mu = 23.9 years     {means that young women are not delaying marriage and marrying at a later age}

Alternate Hypothesis, H_A : \mu > 23.9 years     {means that young women are delaying marriage and marrying at a later age}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                         T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average age of the first time brides = 24.9 years

            \sigma = population standard deviation = 4.2 years

            n = sample of marriage records = 100

So, <u><em>the test statistics</em></u>  =  \frac{24.9-23.9}{\frac{4.2}{\sqrt{100} } }

                                     =  2.381

The value of z test statistics is 2.381.

<u>Now, at 1% significance level the z table gives critical value of and 2.326 for right-tailed test.</u>

Since our test statistic is more than the critical value of z as 2.381 > 2.326, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that young women are delaying marriage and marrying at a later age.

5 0
3 years ago
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