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Answer:
The surface area of the given pyramid is 112 .
Step-by-step explanation:
Base length of the pyramid = 4 inches
Area of the base =
=
= 16
Area of its base = 16
Area of one of its triangular surface = x base x height
= x 4 x 12
= 2 x 12
= 24
Area of all its four triangular surfaces = 4 x 24
= 96
surface area of the pyramid = sum of areas of all its surfaces
= 16 + 96
= 112
The surface area of the given pyramid is 112 .
The area of the garden is 74 square feet
<h3>How to determine the area of the garden?</h3>The complete question is added as an attachment
From the attached figure, we have the following shapes and dimensions:
- Rectangle: 10 by 5 feet
- Trapezoid: Bases = 10 and 6; Height = 3
The rectangular area is
A1 = 10 * 5
Evaluate
A1 = 50
The area of the trapezoid is
A2 = 0.5 * Sum of parallel bases * height
This gives
A2 = 0.5 * (10 + 6) * 3
Evaluate
A2 = 24
The total area is
Total = A1 + A2
This gives
Total = 50 + 24
Evaluate
Total = 74
Hence, the area of the garden is 74 square feet
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