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RSB [31]
3 years ago
11

A punch recipe requires 2 cups of cranberry juice to make 3 gallons of punch. Using the same recipe, what is the amount of cranb

erry juice needed per gallon of punch?
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
4 0

I think it would be 1/2 a cup for 1 gallon...

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The parking garage has 9 rows with 10 parking space in each row . There are 8 empty space . How many space are filled.
tatiyna

Answer:

82 .

Step-by-step explanation:

9x 10 = 90 then 90-8 = 82 that how many spaces are filled .

7 0
3 years ago
I’m confused please helppp
Alborosie
For the first one we see that the shape is that of a parabola and is translated down a few units, We can eliminate linear, exponential
and looking at the general shapes of quadratic and polynomial functions we can conclude that the graph is from a quadratic equation


So Answer is: (2) quadratic

I hope that helps
4 0
3 years ago
1-07 What is the length of the marked portion of each line segment? Copy the
VikaD [51]

Answer:

A. 25 B. 45 C. 30

Step-by-step explanation:

A.

75 ÷ 3 = 25

25 × 1 = 25

B.

75 ÷ 5 = 15

15 × 3 = 45

C.

50 ÷ 5 = 10

10 × 3 = 30

5 0
3 years ago
How can both parents be tall, even though their genes for height are not exactly the same?
SSSSS [86.1K]
Both of the Billy’s parents (calling the parent billy) being tall is a recessive trait therefore both Billy’s parents has to have at least one recessive trait to make a tall child. Billy’s genotype would be way tt (aka recessive, recessive).
5 0
3 years ago
Can you help me with my work
andrezito [222]

Answer:

1. x = ±9

2. x=\pm \sqrt{13}

3. 12 and -12.

4. Antoine is incorrect. There exists two solutions x=5 and x= -5.

Step-by-step explanation:

According to the questions,

Problem 1. x^{2}-81=0 i.e. x^{2}=81 i.e. x = ±9.

Problem 2. 2x^{2}-26=0 i.e. x^{2}-13=0 i.e. x^{2}=13 i.e. x=\pm \sqrt{13}

Problem 3. [tex]f(x)=x^{2}-144[tex]

To find the roots, we take, [tex]x^{2}-144=0[tex] i.e. [tex]x^{2}=144[tex] i.e. x = ±12.

Thus, the options are 12 and -12.

Problem 4. We have [tex]f(x)=x^{2}+25[tex]

For the roots, we take, [tex]x^{2}+25=0[tex] i.e. [tex]x^{2}=25[tex] i.e. x = ±5.

Thus, Antoine is not correct and two solutions namely x=5 and x= -5 exists.

8 0
3 years ago
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