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2 years ago

6. What is the greatest common factor of 12wr2 + 6wr – 6w ?

Mathematics

1 answer:

balandron [24]2 years ago

5 0

Answer:

Step-by-step explanation:

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An electronics store received two shipments of radios. Of the 250 radios in the first shipment, exactly 6% were damaged. In the

nataly862011 [7]

Answer:

Total number of not damaged = 451

C. 451

Step-by-step explanation:

In the first shipment, 6% of the 250 radios where damaged.

Number of damaged= 6/100 * 250

Number of damaged= 6*2.5

Number of damaged= 15 radios.

Number of not damaged= 250-15

Number of not damaged = 235 radios

In the second shipment, 4% of the radios were damaged

Let the number of second shipment= y

0.04 of y where damaged

Total number of radio damaged= 24

15 + 0.04y = 24

0.04y= 24-15

0.04y = 9

Y= 9/0.04

Y= 225

Number of radio in the second shipment= 225

Number of damaged in the second shipment= 0.04*225

Number of damaged in the second shipment= 9

Number of not damaged in the second shipment= 225-9

Number of damaged in the second shipment= 216

Total number of not damaged

= 235+216

= 451

Total number of not damaged= 451

7 0

3 years ago

Higher Order Thinking Mr. Wing's class collected some cans to recycle on Tuesday. They collected 18 more cans on Wednesday. The

Monica [59]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

John and Alan have a collection of x baseball cards. John has x/4 cards. What fraction of the cards does Alan have?

Furkat [3]

The fraction of cards that Alan has is 3x/4. The correct answer is B.

x-x/4
4x-x/4
3x/4
he has 3x/4 cards

3 0

2 years ago

Read 2 more answers

A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain

AysviL [449]

Answer:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

Step-by-step explanation:

For this case we have the following value:

$R = 0.0498 \frac{Kpa}{Km}$

We can convert this first to $\frac{Kpa}{m}$ like this:

$R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}$

Now we use the fact the the pressure is defined as $P =\frac{F}{A}$ , whre P is the pressure, F the force and A the area, so then $Kpa= \frac{KN}{m^2}$ and then we can replace this:

$R=0.0000498 \frac{KN}{m^3}$

Now from definition of work we know that $W= Fd$ where W is the work, F the force and d the distance, so then is equivalent $KN =\frac{KJ}{m}$

And if we replace this into the equation we got:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

4 0

3 years ago

A local grocer wants to find out whether how many mixed flower bouquets in his inventory everyday. To that end, kept records of

Alenkinab [10]

Given:
n = 27, sample size
df = n-1 = 26, degrees of freedom
xb = 11.8, sample mean
s = 2.3, sample standard deviation.

Because population statistics are not known, we should use the Student's t-distribution.
At 99% confidence interval, the t-value = 2.779 (from tables).
The confidence interval is
11.8 +/- 2.779*(2.3/√(27)) = 11.8 +/- 1.23 = (10.57, 13.03)

Answer: (10.6, 13.0) to the nearest tenth

7 0

3 years ago