OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Answer:
10,500
Step-by-step explanation:
See this as 2 rectangles: a box of water (28cm), and another box with the height you want (35cm)
Area of Rectangle = lwh
For the water;
50 x 30 x 28= 42000
As for the needed volume:
50 x 30 x 35 = 52500
To find how much more water, subtract the smaller volume from bigger volume.
10500 should be the final answer
You just find the quartiles which are 62 and 50 the mines them which equals 12.
Answer: 12x+15y
Step-by-step explanation:
Answer:
i think its 358
Step-by-step explanation:
