Write a rule using numbers to find the number of squares in any figure in the pattern

In a certain store, the regular price of a refrigerator is$600. How much money is saved by buying this refrigeratorat 20 percent

Ira Lisetskai [31]

Correct option is A. Money saved is ′ $6 ′ .

Given

Regular price of the refrigerator = $600

i) Buying the refrigerator at 20 percent off regular price

Final Discount in this case = 20% (Regular price of the refrigerator)

= 20 / 100 × 600

= $120

ii) Buying it on sale at 10 percent off regular price and an additional 10 percent off sale price

Discount for the sale = 10% (Regular price of the refrigerator)

= 10/100 × $600

= $60

Sale price of the refrigerator = Regular price of the refrigerator − Discount for sale

= $600 − $60

= $540

Final Discount in this case = 10% (Sale price of the refrigerator)

= 10/100 × $540

= $54

Money saved if we buy as (case−i) = (Final Discount in (case.i)) − (Final Discount in (case.ii))

= $60 − $54

= $6

Therefore, Money saved is ′ $6 ′ .

To learn more about percentage from given link

brainly.com/question/24304697

#SPJ4

4 0

1 year ago

Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)

DiKsa [7]

Answer:

The standard equation of the sphere is $(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Let the first endpoint be represented as $(x_{1}, y_{1}, z_{1})$ and the second endpoint be $(x_{2}, y_{2}, z_{2})$ .

Hence,

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Midpoint = $(\frac{3 + 7 }{2}, \frac{-2+12 }{2}, \frac{4 + 4 }{2})$

Midpoint = $(\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\$

Midpoint = $(5, 5, 4)$

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

$d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2} }$

$d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}$

$d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}$

$d = \sqrt{16 +196 + 0$

$d =\sqrt{212}$

$d = 2\sqrt{53}$

This is the diameter

To find the radius, r

From $Radius = \frac{Diameter}{2}$

$Radius = \frac{2\sqrt{53} }{2}$

∴ $Radius = \sqrt{53}$

r = $\sqrt{53}$

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is $(5, 5, 4)$

Radius of the sphere is $\sqrt{53}$

The equation of a sphere of radius r and center $(h,k,l)$ is given by

$(x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}$

Hence, the equation of the sphere of radius $\sqrt{53}$ and center $(5, 5, 4)$ is

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}$

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

This is the standard equation of the sphere

6 0

3 years ago

What is( 5×100)+(6x10)+(8×1/10)+(9×1/1,000) in standard form

nadya68 [22]

Answer:

6x^10+2504/5+(9*1/1,0)

Step-by-step explanation:

Hope this helps :)

5 0

3 years ago

Please help me, and please explain how you get to the answer.

Sliva [168]

the answer is 16

8^(4/3) can be written in different ways. You can first simplify it by breaking the exponents down into 1/3 and 4. You can write it as (8^1/3)^4 (it still means the same thing). When you raise something to the one over something fraction, the denominator tells you what the root is. Because it says 1/3, it means that you're finding the cube root of something. So you can rewrite it as (3√8)^4 (the three should be sitting on top of the sign to signify that it's cube root). You then just solve from there. The cube root of 8 is 2 (2*2*2=8) so it'll simplify to (2)^4. You then solve it from there and get 16 as your answer (2*2*2*2=16).

5 0

3 years ago

I need help please! <br> 3/10×(−4/5)

Tems11 [23]

-0.24 should be the answer. idk i might be wrong. im not to great at math just i just used a calculator

6 0

3 years ago

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