Let us take the second equation first
2a + 2b = 6
Dividing both sides by 2 we get
a + b = 3
a = 3 - b
Putting the value of a in the first equation we get
3a + 4b = 9
3(3 - b) + 4b = 9
9 - 3b + 4b = 9
b = 9 - 9
= 0
Now putting the value of b in the second equation we get
a + b = 3
a + 0 = 3
a = 3
So the value of the unknown variable a is 3 and the value of the unknown variable b is 0.
k, n - integers
2k+1 - an odd integer
2n+1 - another odd integer
The product of them:
(2k + 1)(2n + 1) =
= 4kn + 2k + 2n + 1 =
= 2(2kn + k + n) + 1
The product of integers (2kn) is integer
and the sum of them (2kn+k+n) also is integer
So (2k + 1)(2n + 1) = 2(2kn + k + n) + 1 is an odd integer
Answer:
B. (-2,-4)
Explanation
Given equations:
y = 3x + 2
y = -2x - 8
Solving both equations will yield the values of x and y;
Solution:
y = 3x + 2 ----- (i)
y = -2x - 8 ------ (ii)
Using substitution method, input equation i, into ii
3x + 2 = -2x - 8
Collect like terms and solve;
3x + 2x = -8 -2
5x = -10
x = -2
Then put x = -2 into i, to find y
y = (-2 x 3) + 2
y = -6 + 2 = -4
So, the solution of the equation is B. (-2,-4)
12 × 2 = 24
24 × 3 = 72
72 × 4 = 288
288 × 5 = 1,440, and so on...
<span><span>Comments </span> <span>Report</span></span>
