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kolbaska11 [484]
3 years ago
12

P(×)= x(2x + 1)- 6x-3 Factorize p(×) ​

Mathematics
1 answer:
kherson [118]3 years ago
4 0

Step-by-step explanation:

P(X)=2x²-5x-3 is in the form ax²+bx+c

Using quadratic equation

x={-b±√(b²-4ac)}/2a

x=3,-1/2

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The hare challenged the tortoise to a race from the water fountain to the park bench. In order to ensure a fair race, the tortoi
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A. I believe the hare never catches up to the tortoise
B. The hare waited 50 minutes before walking
C. The tortoise won the race
5 0
2 years ago
In triangles DEF and OPQ, ∠D ≅ ∠O, ∠F ≅ ∠Q, and segment DF ≅ segment OQ. Is this information sufficient to prove triangles DEF a
kenny6666 [7]

In triangles DEF and OPQ, ∠D ≅ ∠O, ∠F ≅ ∠Q, and segment DF ≅ segment OQ; this is not sufficient to prove triangles DEF and OPQ congruent through SAS

<h3>What are congruent triangles?</h3>

Two triangles are said to be congruent if they have the same shape, all their corresponding angles as well as sides must also be congruent to each other.

Two triangles are congruent using the side - angle - side congruency if two sides and an included angle of one triangle is congruent to that of another triangle.

In triangles DEF and OPQ, ∠D ≅ ∠O, ∠F ≅ ∠Q, and segment DF ≅ segment OQ; this is not sufficient to prove triangles DEF and OPQ congruent through SAS

Find out more on congruent triangle at: brainly.com/question/1675117

#SPJ1

8 0
1 year ago
Given the function f(x)=-8x2+8x+9,state whether the vertex represents a maximum or minimum point for the function.
Lelechka [254]
8x2+8x+9
=16x+8x+9
=24x+9
Are that right
5 0
3 years ago
Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the
ziro4ka [17]

Answer:

a) \frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case we need to find the sample standard deviation with the following formula:

s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}&#10;And in order to find the sample mean we just need to use this formula:&#10;[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=9-1=8

The Confidence interval is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and the critical values are:

\chi^2_{\alpha/2}=20.09

\chi^2_{1- \alpha/2}=1.65

And replacing into the formula for the interval we got:

\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0
3 years ago
Can you guys help me with #13 please I don't get it
Furkat [3]
Your taking off $20 from the amount that you have to begin with
5 0
3 years ago
Read 2 more answers
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