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Vitek1552 [10]
3 years ago
11

Which 90% of your brain would you like to remove while driving a car? Explain/defend your answer.

Physics
1 answer:
Hatshy [7]3 years ago
6 0

The human beings use 10 % of the brain and the remaining  90 percent is full of unused potential and undiscovered abilities.

Explanation:

It is stated that every human beings use 10 percent of their brain and the other 90 percent is used only for operating a limited stretch. the average adult human brain can store the 2.5 million gigabytes digital memory.

The human brains contains about 100 billion neurons and around i quadrillion to 1 million connections in the cells. The dendrites provide more information than passive wiring.

The unused part of the brain is not necessary it simply occupies the space. The damaged parts of the brain should be removed.

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A stack of books whose true weight is 165 N is placed on a scale in an elevator. The scale reads 165 N. Can you tell from this i
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Answer:

D) not enough information to decide

Explanation:

Data provided in the question

The True weight of book stacks = 165 N

Reading of the scale = 165 N

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Based on the above information

If you moved at a constant velocity the scale interprets the same because of the momentum you've got. The scale will change the number only when acceleration is present.

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Which phrases apply to the formation of the Grand Canyon?
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Large scale

Explanation:

short term

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When red light and green light shine on the same place on a piece of white paper, the spot appears t obe?
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4 years ago
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What is the energy stored in the 10.5 μ F 10.5 μF capacitor of a heart defibrillator charged to 8250 V ?
Kay [80]

Answer:

356.33 J

Explanation:

Energy: This can be defined as the ability or the capacity to do work. The S.I unit of Energy is Joules (J).

The Energy stored in a capacitor = 1/2CV²

E = 1/2CV².............................. Equation 1.

Where E = Energy stored in a capacitor, C = capacitance of the capacitor, V = potential difference across the plates of the capacitor.

Given: C = 10.5 μF  = 10.5×10⁻⁶ F, V = 8250 V.

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Thus the energy stored in the defibrillator = 356.33 J

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