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icang [17]
3 years ago
5

A stone is thrown from the top of a building with an initial velocity of 20 m/s downward. The top of the building is 60 m above

the ground. How much time elapses between the instant of release and the instant of impact with the ground
Physics
1 answer:
erastova [34]3 years ago
6 0

Answer:

t = 2 s

Explanation:

In order to find the time taken by the stone to fall from the top of the building to the ground we can use 2nd equation of motion. 2nd equation of motion is as follows:

s = Vit + (0.5)gt²

where,

t = time = ?

Vi = Initial Velocity = 20 m/s

s = height of building = 60 m

g = 9.8 m/s²

Therefore,

60 m = (20 m/s)t + (0.5)(9.8 m/s²)t²

4.9t² + 20t - 60 = 0

solving this quadratic equation we get:

t = -6.1 s   (OR)   t = 2 s

Since, the time cannot be negative in magnitude.

Therefore,

<u>t = 2 s</u>

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A particle on a spring moves in simple harmonic motion along the x axis between turning points at x1 = 95 cm and x2 = 135 cm. (i
uranmaximum [27]

Answer:

(i) x = 115\,cm, (ii) x = 95\,cm, (iii) x = 95\,cm

Explanation:

(i) x_{1} and x_{2} represent the points where particle has a velocity of zero and spring reach maximum deformation, Given the absence of non-conservative force and by the Principle of Energy Conservation, the position where particle is at maximum speed is average of both extreme positions:

x = 115\,cm

(ii) Maximum accelerations is reached at x_{1} and x_{2}.

x = 95\,cm

(iii) Greatest net forces exerted on the particle are reached at  x_{1} and x_{2}.

x = 95\,cm

8 0
3 years ago
what is the acceleration of each body of mass 5kg rests on a frictionless table and is connected to a cable that passes over a p
Oksanka [162]

Answer:

6.53 m/s²

Explanation:

Let m₁ = 5 kg and m₂ = 10 kg. The figure is attached and free body diagrams of the objects are also attached.

Both objects (m₁ and m₂) have the same magnitude of acceleration(a). Let g be the acceleration due to gravity = 9.8 m/s². Hence:

T = m₁a               (1)

m₂g - T = m₂a    (2)

substituting T = m₁a in equation 2:

m₂g - m₁a = m₂a

m₂a + m₁a = m₂g

a(m₁ + m₂) = m₂g

a = m₂g / (m₁ + m₂)

a = (10 kg * 9.8 m/s²) / (10 kg + 5 kg) = 6.53 m/s²

Both objects have an acceleration of 6.53 m/s²

8 0
3 years ago
Yall i need this asap
liq [111]
ASAP Ferg?
Edge 2020
6 0
2 years ago
Un joven pelotero llamado Saúl en su primer año de ser firmado en grandes ligas, batea varias veces de cuadrangular, el segundo
Brilliant_brown [7]

Answer:

135-15=120

120÷3=40

40+40+(10)+40+(5)=135

8 0
2 years ago
Read 2 more answers
2. What type of motion objects that fall under the pull of gravity?
vivado [14]
<u><em>Kinetic Energy Pulls Any object to the ground.This Energy is a part of Gravity.</em></u>
<u><em>Wish you happy timez!</em></u>
4 0
3 years ago
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