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kotykmax [81]
3 years ago
10

i need to know The Sun and Moon seem to move across the sky each day because of Earth's ____________________ on its axis. The Mo

on can be seen from Earth because ____________________ reflects off the Moon's surface. Any object that revolves around another object in space is called a(an) ____________________.
Physics
1 answer:
tester [92]3 years ago
8 0
I don’t know the first one but the second one is light and the third one is a satellite
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SOME ONE PLZ HELP WILL GIVE THE BRAINIEST
Keith_Richards [23]

Answer:

I. 90%

II. 60 MW

Explanation:

From the question given above, the following data were obtained:

Power input = 600 MW

Power output = 540 MW

I. Determination of the efficiency.

Power input = 600 MW

Power output = 540 MW

Efficiency =?

Efficiency = output / input × 100

Efficiency = 540 / 600 × 100

Efficiency = 90%

II. Determination of the power wasted by the pump.

Power input = 600 MW

Power output = 540 MW

Power wasted =?

Power wasted = Power input – Power output

Power wasted = 600 – 540

Power wasted = 60 MW

4 0
2 years ago
Which type of matter is likely to absorb the most sound waves? A. Metal door B. Loudspeaker C. Hot air O D. Foam wall​
alina1380 [7]

Answer:

I think D...

Explanation:

6 0
3 years ago
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How could you decrease the total energy of a system consisting of a jar full of water? O A. Heat the jar in a microwave oven. O
Vaselesa [24]

Answer:

A

Explanation:

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3 years ago
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The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with acceleration of −5.2
sergejj [24]

Answer:

The car strikes the tree with a final speed of 4.165 m/s

The acceleration need to be of -5.19 m/seg2 to avoid collision by 0.5m

Explanation:

First we need to calculate the initial speed V_{0}

x=V_{0} *t+\frac{1}{2} *a*(t^{2} )\\62.5m=V_{0} *4.15s+\frac{1}{2} *-5.25\frac{m}{s^{2} } *(4.15^{2} )\\V_{0}=25.953\frac{m}{s}

Once we have the initial speed, we can isolate the final speed from following equation:

V_{f} =V_{0} +a*t  V_{f}= 4.165 \frac{m}{s}  

Then we can calculate the aceleration where the car stops 0.5 m before striking the tree.

To do that, we replace 62 m in the first formula, as follows:

x=V_{0} *t+\frac{1}{2} *a*(t^{2} )\\62m=25.953\frac{m}{s}*4.15s+\frac{1}{2} *-a\frac{m}{s^{2} } *(4.15^{2} )\\a=-5.19\frac{m}{s^{2} }

3 0
3 years ago
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CAN SOMEONE PLEASE TELL ME WHAT THIS WHEEL IS CALLED.WILL GIVE BRAINLIEST
kolbaska11 [484]

Answer:

its a pie chart

Explanation:

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