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3 years ago

What’s the temperature 15 Fahrenheit in degrees Celsius ?

Physics

1 answer:

Ierofanga [76]3 years ago

3 0

Answer:

-9.44444

Formula: (15°F-32) ×5/9= -9.44444

Hope this helped :)

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The air around a pool and the water in the pool receive equal amounts of energy from the sun. Why does the air experience a grea

labwork [276]

Answer:

Explanation:

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3 years ago

If you were to make a three-dimensional model of magnetic force using a magnet and magnetic field lines, which two characteristi

kkurt [141]

Answer:

- the Magnetic field lines will spread out of the north end of the magnet.

- the magnetic fields will three-dimensional and resemble a bubble.

Explanation:

- Usually, when drawing magnetic field lines, we start outwardly from the North pole to the South Pole. This same direction is also prevalent on the Earth due to the fact that the Earth functions as a giant magnet. Thus, one characteristic of the model is that the Magnetic field lines will spread out of the north end of the magnet.

- Another thing is that Magnetic field forces are usually driven as a result bubble like configuration which affects the objects that are in such a configuration. Thus, another characteristic of the model is that the magnetic fields will three-dimensional and resemble a bubble.

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3 years ago

7. Find the speed of a 22 kg mass with a momentum of 450 kgm/s. (Round

jeyben [28]

Answer:

i don't know if this is right but here,9900 kgm/s

Explanation:

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4 years ago

At time t=0 a proton is a distance of 0.360 m from a very large insulating sheet of charge and is moving parallel to the sheet w

Yuki888 [10]

Explanation:

Formula for the electric field due to the infinite sheet of charge is as follows.

E = $\frac{\sigma}{2 \epsilon_{o}}$

where, $\sigma$ = surface charge density

Now, formula for electric force acting on the proton is as follows.

F = eE

where, e = charge of the proton

According to the Newton's second law of motion, the net force acting on the proton is as follows.

F = ma

a = $\frac{eE}{m}$

= $\frac{e(\frac{\sigma}{2 \epsilon_{o}})}{m}$

= $\frac{e \sigma}{2m \epsilon_{o}}$

According to the kinematic equation, speed of the proton in perpendicular direction is as follows.

$v_{f} = v_{i} + at$

= $(0 m/s) + \frac{e \sigma}{2 m \epsilon_{o}}t$

= $\frac{1.6 \times 10^{-19}C \times 2.34 \times 10^{-9} C/m^{2} \times 5.40 \times 10^{-8}s}{2 \times (1.67 \times 10^{-27} kg)(8.85 \times 10^{-12} C^{2}/Nm^{2}}$

= 683.974 m/s

Hence, total speed of the proton is as follows.

v' = $\sqrt{(960 m/s)^{2} + (683.974 m/s)^{2}}$

= $\sqrt{921600 + 467820.43}$

= $\sqrt{1389420.43}$

= 1178.73 m/s

Therefore, we can conclude that speed of the proton is 1178.73 m/s.

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3 years ago

If there is no friction in a rollercoaster is the speed the same throughout?

andrey2020 [161]

If there is no friction, the roller coaster would keep moving forever but a constant velocity. The only way it would accelerate is if there was a force continually pushing on it.

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3 years ago

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