If there is no friction in a rollercoaster is the speed the same throughout?
2 answers:
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Answer:
a) See attachment.
b) a_avg = -8.66 i - 2.33 j
c) a = 195 degrees from + x-axis. |a_avg| = 8.97 m/s^2
Explanation:
Given:
- Initial Velocity V_i = (90 i + 110 j)
- Final velocity V_f = (-170 i + 40 j)
- t_i = 0
- t_f = 30.0 s
Find:
(a) Sketch the velocity vectors at t1 and t2. How do these two vectors differ?
(b) the components of the average acceleration
(c) the magnitude and direction of the average acceleration.
Solution:
- The change in velocity is given by:
Δ V = (V_f - V_i)
Δ V = ( -170 i - 90 i + 40 j - 110 j)
Δ V = (-260 i - 70 j)
- The change in time is given as:
Δ t = t_f - t_i = 30 - 0 = 30 s
-The average acceleration is:
a_avg = Δ V / Δ t
a_avg = (-260 i - 70 j) / 30
a_avg = -8.66 i - 2.33 j
- The magnitude of acceleration is:
|a_avg| = sqrt ( 8.66^2 + 2.33^2)
|a_avg| = sqrt (80.4245)
|a_avg| = 8.97 m/s^2
- The direction of acceleration is given by:
tan (Q) = a_y / a_x
Q = arctan(a_y / a_x)
Q = arctan(2.33 / 8.66)
Q = 15 degrees
Hence, 180 + 15 = a. a = 195 degrees from + x-axis.
Answer:
La cantidad de movimiento es 1,92 kg*m/s.
Explanation:
La cantidad de moviemiento de la masa esta dado por:
En donde:
p: es la cantidad de moviemiento o momento =?
m: es la masa = 4570 g
v: es la velocidad = 1,5 km/h
Tenemos que 1 kg = 1000 g, por lo tanto la masa es:
Ahora debemos convertir la velocidad de km/h a m/s:
Entonces, el momento es:
Por lo tanto, la cantidad de movimiento es 1,92 kg*m/s.
Espero que te sea de utilidad!