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4 years ago

They are rare and can only be seen from certain locations on Earth when they occur. true or false?

Physics

2 answers:

wariber [46]4 years ago

4 0

False
I think?bla bla bla bla that is what is going through y brain right now I don't know why

hammer [34]4 years ago

3 0

It is true. You have to be on the sunny side on earth for lunar eclipses.

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. Two identical blocks, each of mass M, are connected by a massless string over a pulley of radius R and moment of inertia I. Th

Dima020 [189]

The angular acceleration of a pulley is described under the equation,

$\theta = (0.5) \alpha t^2$

So things clearing,

$\alpha = \frac{ 2\theta}{t^2}$

b) For point B it is necessary to make a sum of Forces,

$\sum F=0$

In this way,

$Mg - T_1 = Ma$

$T_1 = Mg - Ma$ (1)

For block 2, we have the following relationship,

$T_2 = Ma$ (2)

So,

$T_1 - T_2 = I \frac{a}{R}$ (3)

Substituting (1) and (2) in (3)

$Mg - Ma - Ma = I \frac{a}{R}$

So,

$a = \frac{2\theta R}{t^2}$

<em>**Note that</em> $\alpha R = a$

c) For this point we need to use (1)

$T1 = Mg - Ma = Mg - \frac{M^2\theta R}{t^2}$

using (2)

$RT_2=RT_1-I\alpha$

$T_2= \frac{RM(g-\frac{2\theta R}{t^2})-I\frac{2\theta}{t^2}}{R}$

$T_2=\frac{RMgt^2-2R^2M\theta-2t\theta}{Rt^2}$

5 0

3 years ago

A future use of space stations may be to provide hospitals for severely burned persons. It is very painful for a badly burned pe

inessss [21]

Answer:

1.5min

Explanation:

To solve the problem it is necessary to take into account the concepts related to Period and Centripetal Acceleration.

By definition centripetal acceleration is given by

$a_c = \frac{V^2}{r}$

Where,

V = Tangencial velocity

r = radius

With our values we know that

$a_c = \frac{V^2}{r}$

$\frac{V^2}{r} = \frac{1}{10}g$

Therefore solving to find V, we have:

$V = \sqrt{\frac{1}{10}g*r}$

$V = \sqrt{\frac{9.81*200}{10}}$

$V = 14m/s$

For definition we know that the Time to complete are revolution is given by

$t = \frac{Perimeter}{Speed}$

$t = \frac{2\pi R}{V}$

$t = \frac{2\pi * 200}{14}$

$t = 1.5min$

6 0

3 years ago

Jenise is buying a car for $13,085. She wants $9,400 in upgrades to the car.

inysia [295]

Answer:

$55.6

Explanation:

sorry sorry sorry sorry sorry

3 0

3 years ago

Read 2 more answers

How do X-rays and ultrasounds differ ?

Nonamiya [84]

Ultrasound is vibrations, just like sound is vibrations. Ultrasound travels though the body just like sound would and when it hits something, it bounces back, where it is picked up by a receiver. which then makes an image out of it.

X-rays are electromagnetic waves, like visible light. Other examples of electromagnetic waves are infrared, and ultraviolet. But people cant see infrared nor ultraviolet, even though they are just like visible light. The difference between visible light and all these other kinds of light are just like the difference between red and blue. They are both light but different colors, ultraviolet and infrared are colors we cannot see, and in fact, we can see only a tiny portion of the colors out there. X-rays are just like all these kinds of light and we cant see it but it is able to go through most of the body, bot not bone. Doctors use x-rays to see bones and things like that in the body because x-rays won't pass through bone, but they will go through muscle and skin. So when a doctor takes an x-ray, its just like making a silhouette, but with colors we cant see. Of course, the x-rays make the photo paper change color and that's how we are able to see the image but the principle is the same.

7 0

4 years ago

Calculate the object's velocity as shown on the position-time graph,

Cloud [144]

Answer:

10 m/s

Explanation:

The following data were obtained from the question:

Initial Displacement (d1) = 10 m

Final Displacement (d2) = 60 m

Initial time (t1) = 0 s

Final time (t2) = 5 s

Velocity (v) =.?

Next, we shall determine the change in displacement of the object and likewise the change in time.

This can be obtained as follow:

Initial Displacement (d1) = 10 m

Final Displacement (d2) = 60 m

Change in displacement (Δd) = d2 – d1

Change in displacement (Δd) = 60 – 10

Change in displacement (Δd) = 50 m

Initial time (t1) = 0 s

Final time (t2) = 5 s

Change in time (Δt) = t2 – t1

Change in time (Δt) = 5 – 0

Change in time (Δt) = 5 s

Finally, we shall shall calculate the velocity of the object as illustrated below:

Change in displacement (Δd) = 50 m

Change in time (Δt) = 5 s

Velocity (v) =.?

v = Δd/Δt

v = 50/5

v = 10 m/s

Therefore, the velocity of the object is 10 m/s.

4 0

3 years ago