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exis [7]
4 years ago
5

They are rare and can only be seen from certain locations on Earth when they occur. true or false?

Physics
2 answers:
wariber [46]4 years ago
4 0
False
 I think?bla bla bla bla that is what is going through  y brain right now I don't know why
hammer [34]4 years ago
3 0
It is true. You have to be on the sunny side on earth for lunar eclipses.
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Which of the following signs on q and w represent a system that is doing work on the surroundings, as well as losing heat to the
Karolina [17]

Answer:c

Explanation:

In Physics we follow the sign convention i.e. work done by the system is considered as positive i.e. work is being done by system on the surrounding and vice-versa.

For heat :Heat added to the system is considered as Positive while heat loss to surrounding is considered as negative.

thus doing work on the surrounding(work done by system) w=+

Losing heat to the surrounding q=-

3 0
3 years ago
Read 2 more answers
Diagnostic ultrasound of frequency 4.50 MHz is used to examine tumors in soft tissue. (a) What is the wavelength in air of such
mafiozo [28]

(a) 7.62 \times 10^{-5} m is the wavelength in air of such a sound wave.

(b) 3.33 \times 10^{-4}\ m is the wavelength of this wave in tissue.

<u>Explanation:</u>

Frequency and wavelength can be related by the equation,

              Velocity = Wavelength x Frequency

              v=\lambda \times f

where,

v - velocity of light for all EM (electromagnetic) waves in vacuum

Given:

f - 4.50 MHz = 4.50 \times 10^{6} \mathrm{Hz}

a) To find the wavelength in air

We know,

Speed of sound in air = 343 m/s

Apply given frequency and speed of sound in air, we get

        \lambda=\frac{v}{f}=\frac{343}{4.5 \times 10^{6}}=76.2 \times 10^{-6}=7.62 \times 10^{-5}\ \mathrm{m}

b) If the speed of sound in tissue is 1500 m/s, find the wavelength of this wave in tissue

Speed of sound in tissue, v = 1500 m/s

        \lambda=\frac{v}{f}=\frac{1500}{4.5 \times 10^{6}}=333.33 \times 10^{-6}=3.33 \times 10^{-4} \mathrm{m}

4 0
3 years ago
A net downward force of 20 N causes a book to fall towards the ground at m/s2. What is the book’s mass? Consider air resistance
stira [4]

If we have to figure air resistance into it, then we don't have enough information to find an answer.  

If the air around it is going to have an effect on how it falls, then it'll depend on the thickness of the book, the shape of the book, whether it's a hard-cover or soft-cover, how far the covers stick out past the pages, how smooth or rough the covers are, how bumpy the binding it. and what position you hold it in before you let it go.

(THAT's why we always ignore air resistance, especially when the question is actually about gravity anyway.)

4 0
3 years ago
What are the properties of water from a glacier and a geyser that are the same
Sav [38]
The only common property is that both of those things are comprised of H2O.
7 0
4 years ago
Mercury has a mass of 3.3 e 23 kg and a radius of 2.44 e 6 m. Find Mercury's
valentina_108 [34]

Answer:

11.) g = 3.695 m/s^2

12.) g = 8.879 m/s^2

13.) E = 8127 N/C

Explanation:

11.) Given that the

Mercury mass M = 3.3 × 10^23kg

Radius r = 2.44 ×10^6 m

Gravitational constant G = 6.67408 × 10^-11 m3kg-1 s^-2

Gravitational field strength g can be calculated by using the formula below

g = GM/r^2

Substitutes all the parameters into the formula

g = (6.67408 × 10^-11 × 3.3 × 10^23)/(2.44×10^6)^2

g = 2.2×10^13/5.954×10^12

g = 3.695 m/s^2

12.) Given that the

Venus mass M = 4.87×10^24kg

Radius r = 6.05 × 10^6 m

Using the same formula for gravitational field strength g

g = GM/R2

Substitute all the parameters into the formula

g = (6.67408 × 10^-11 × 4.87×10^24)/(6.05×10^6)^2

g = 3.25×10^14/3.66×10^13

g = 8.879 m/s^2

13.) Given that the

Charge = 2.26 nC = 2.26×10^-9

Distance d = 0.05m

Electric field strength E can be calculated by using the formula below

E = Kq/d^2

Where

K = electrostatic constant 8.99 × 10^9 Nm2/C2

Substitutes all the parameters into the formula

E = (8.99 × 10^9 × 2.26×10^-9)/0.05^2

E = 20.3174/2.5×10^-3

E = 8126.96 N/C

7 0
4 years ago
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