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anzhelika [568]
3 years ago
6

consider the line y=2/3x-0 find the equation of the line that is parallel to this line and passes through the point(8, 4).

Mathematics
1 answer:
Mila [183]3 years ago
4 0
To find the equation take the slope 2/3 y-y(1)=m(x-x(1) y-4=2/3(x-8) = 2/3x-16/3 Next solve for y y=2/3x-16/3 +4(turn 4 into a fraction with a common denominator) y=2/3x-16/3 + 12/3 y=2/3x-4/3
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Advocard [28]
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Elza [17]

Answer:

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Step-by-step explanation:

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LenaWriter [7]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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nevsk [136]

Answer:

arc AB = 70°

arc BC = 110°

arc ABC = 180°

arc CDB = 250°

Step-by-step explanation:

Since these angles are not inscribed, but are at the center point of the circle, the angles and arcs will be the same measure.

Solve for arc AB:

Angle AFB = 70°, so arc AB = 70°

Solve for arc BC:

Angle AFC is a straight angle so it is 180°. To find angle BFC, subtract angle AFB from 180°.

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Add arc AB and arc BC together.

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Solve for arc CDB:

There are 360° in a cirlce. To find arc CDB, subtract arc BC from 360°.

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