consider the line y=2/3x-0 find the equation of the line that is parallel to this line and passes through the point(8, 4).
1 answer:
To find the equation take the slope 2/3
y-y(1)=m(x-x(1)
y-4=2/3(x-8) = 2/3x-16/3
Next solve for y
y=2/3x-16/3 +4(turn 4 into a fraction with a common denominator)
y=2/3x-16/3 + 12/3
y=2/3x-4/3
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