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anzhelika [568]
3 years ago
6

consider the line y=2/3x-0 find the equation of the line that is parallel to this line and passes through the point(8, 4).

Mathematics
1 answer:
Mila [183]3 years ago
4 0
To find the equation take the slope 2/3 y-y(1)=m(x-x(1) y-4=2/3(x-8) = 2/3x-16/3 Next solve for y y=2/3x-16/3 +4(turn 4 into a fraction with a common denominator) y=2/3x-16/3 + 12/3 y=2/3x-4/3
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I have one question, i'll give ya'll 50 points!
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Find a formula for the described function. An open rectangular box with volume 3 m3 has a square base. Express the surface area
Alex73 [517]

Answer:

SA(x) = x^2 + \frac{12}{x}

Step-by-step explanation:

Given

V = 3m^3 --- volume

x \to base\ length

y \to height

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The surface area as a function of base length

The volume (V) is calculated as:

V = Base\ Area * Height

V = x*x*y

V = x^2*y

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y = \frac{V}{x^2}

Substitute 3 for V

y = \frac{3}{x^2}

The surface area of the open box is:

SA = x^2 + 2xy+2xy

SA = x^2 + 4xy

Substitute: y = \frac{3}{x^2}

SA = x^2 + 4x*\frac{3}{x^2}

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4 0
3 years ago
Answer for <br> 5.3 (2×+5)=
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Step-by-step explanation:

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Answer:

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2 years ago
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Oliga [24]

Answer:

x = 18

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x+x+x=54

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Step 2: Divide both sides by 3.

3x  3 = 54

3 x=18

Answer:

x=18

8 0
3 years ago
Read 2 more answers
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