Which decimal is equivalent to 7.44343434...?

Is the length and width of a square equal?

Semenov [28]

Answer:

Yes.

Step-by-step explanation:

Each side of a square must be congruent and parallel to its opposite side.

6 0

3 years ago

Center ( 9,-8 ), passes through ( 19,22 )

katovenus [111]

Center at (h,k) and radius r is
(x-h)²+(y-k)²=r²

so given
center at (9,-8)

(x-9)²+(y-(-8))²=r²
(x-9)²+(y+8)²=r²

input the point (19,22) to find r²
x=19 and y=22
(19-9)²+(22+8)²=r²
10²+30²=r²
100+900=r²
1000=r²
10√10=r

well, the equation is
(x-9)²+(y+8)²=1000

6 0

4 years ago

First derivative of <br>√{cosec2x).show with full step.

Mice21 [21]

Answer:

$- \sf \displaystyle \: \frac{ \cos(2x) }{ \sin ^{2} (2x)\sqrt{ \csc(2x) } }$

Step-by-step explanation:

we are given a derivative

$\displaystyle \: \frac{d}{dx} ( \sqrt{ \csc(2x) } )$

and said to figure out the first derivative

to do so

recall chain rule:

$\sf\displaystyle \: \frac{d}{dx} (f(g(x)) = \frac{d}{dg} (f(g(x)) \times \frac{d}{dx} (g)$

so we get

$\displaystyle \: g(x) = \csc(2x)$

rewrite the derivative using the chain rule:

$\displaystyle \: \frac{d}{dg} ( \sqrt{ g } ) \times \frac{d}{dx} ( \csc(2x) )$

use square root derivative rule to simplify:

$\displaystyle \: \frac{1}{ 2\sqrt{g} } \times \frac{d}{dx} ( \csc(2x) )$

now we need to again use chain rule composite function derivative to simplify

where we'll take a new function n so we won't mess up two g's and we'll take 2x as n

use composite function derivative to simplify:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{g} } \times \frac{d}{dn}( \csc(n) ) \times \frac{d}{dx} (2x)$

use derivative formula to simplify derivatives:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{g} } \times - \cot(n) \csc(n) \times 2$

substitute the value of n:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{g} } \times - 2\cot(2x) \csc(2x)$

substitute the value of g:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{ \csc(2x) } } \times - 2\cot(2x) \csc(2x)$

now we need our trigonometric skills to simplify

rewrite cot and csc:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{ \csc(2x) } } \times - 2 \dfrac{ \cos(2x) }{ \sin(2x) } \dfrac{1}{ \sin(2x) }$

simplify multiplication:

$\sf \displaystyle \: \frac{1}{ \cancel{ \: 2}\sqrt{ \csc(2x) } } \times \cancel{- 2} \dfrac{ \cos(2x) }{ \sin ^{2} (2x) }$

simplify multiplication:

$- \sf \displaystyle \: \frac{ \cos(2x) }{ \sin ^{2} (2x)\sqrt{ \csc(2x) } }$

4 0

3 years ago

Read 2 more answers

PLEASE HELP!!!!!!!!

Anastaziya [24]

Answer:

There are 76 students:

g + b = 76

girls is 13 more than twice the boys:

g = 2b + 13

replace g with 2b + 13 in 1st equation

2b+13+b = 76

3b + 13 = 76

3b = 63

b = 21 boys

g = 76-21 = 55 girls

Step-by-step explanation:

8 0

3 years ago

Identify like terms 2d 5f 2g 7 3g g

ira [324]

Answer:

Step-by-step explanation:

The degrees of the terms in the order given are 2, 4, 1, 3, 0. The second-highest of these numbers is 3, and the corresponding term is ...

B: -g^3

(3g+5)(2g-7)

(3g+5)(2g-7)=6g²-21g+10g-35 = 6g²-11g-35

7 0

3 years ago