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exis [7]
2 years ago
12

3-i------4+2iI don't understand what I need to do here

Mathematics
1 answer:
Vinvika [58]2 years ago
4 0
The answer is the one that's bettween 3-i and 4+2i is 5x 2i
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The radius of a spherical balloon is measured as 20 inches, with a possible error of 0.03 inch. Use differentials to approximate
soldi70 [24.7K]

Answer:

a) V = 33510.322\,in^{3}, b) A_{s} = 5026.548\,in^{2}, c) \% V = 0.450\,\%, \%A_{s} = 0.300\,\%.

Step-by-step explanation:

The volume and the surface area of the sphere are, respectively:

V = \frac{4}{3}\pi \cdot r^{3}

A_{s} = 4\pi \cdot r^{2}

a) The volume of the sphere is:

V = \frac{4}{3}\pi \cdot (20\,in)^{3}

V = 33510.322\,in^{3}

b) The surface area of the sphere is:

A_{s} = 4\pi \cdot (20\,in)^{2}

A_{s} = 5026.548\,in^{2}

c) The total differentials for volume and surface area of the sphere are, respectively:

\Delta V = 4\pi\cdot r^{2}\,\Delta r

\Delta V = 4\pi \cdot (20\,in)^{2}\cdot (0.03\,in)

\Delta V = 150.796\,in^{3}

\Delta A_{s} = 8\pi\cdot r \,\Delta r

\Delta A_{s} = 8\pi \cdot (20\,in)\cdot (0.03\,in)

\Delta A_{s} = 15.080\,in^{2}

Relative errors are presented hereafter:

\%V = \frac{\Delta V}{V}\times 100\%

\%V = \frac{150.796 \,in^{3}}{33510.322\,in^{3}}\times 100\,\%

\% V = 0.450\,\%

\% A_{s} = \frac{\Delta A_{s}}{A_{s}}\times 100\,\%

\% A_{s} = \frac{15.080\,in^{2}}{5026.548\,in^{2}}\times 100\,\%

\%A_{s} = 0.300\,\%

4 0
3 years ago
The answer <br> A<br> B<br> C<br> D<br> ?
Anna11 [10]

Answer:C

Step-by-step explanation:

6 0
3 years ago
Describe how the graph of y= 1/3x is the same and different from the graph of y= 1/3x - 4
uranmaximum [27]

Answer:

the lines have the same slope

the y-intercept of the lines are different

Step-by-step explanation:

7 0
3 years ago
Use the diagram of point O. What is the length of OY to the nearest 10th of an Inch? XZ = 10 and OX= 10
Lady bird [3.3K]

From the diagram above,

XZ = 10 in and OX = 10 in

we are to find length of OY

XZ is a chord and line OY divides the chord into equal length

Hence, ZY=YX= 5 in

Now we solve the traingle OXY

To find OY we solve using pythagoras theorem

(Hyp)^2=(Opp)^2+(Adj)^2

applying values from the triangle above

\begin{gathered} OX^2=XY^2+OY^2 \\ 10^2=5^2+OY^2 \\ 100=25+OY^2 \\ OY^2\text{ = 100 -25} \\ OY^2\text{ = 75} \\ OY\text{ = }\sqrt[]{75} \\ OY\text{ = }\sqrt[]{25\text{ }\times\text{ 3}} \\ OY\text{ = 5}\sqrt[]{3\text{ }}in \end{gathered}

Therefore,

Length of OY =

5\sqrt[]{3}

8 0
11 months ago
Hey does anyone know this
Readme [11.4K]
- Use the formula V = π <span>∙ r2 ∙ h.
- Plug into the equation. 27</span>π(cubed)=π∙3(2)∙h
-Solve. 27π(3)=9π∙h
27π/9π=3π
I believe the height is 3π.
<span>Hope this helps

</span>
8 0
3 years ago
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