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3 years ago

In order to solve the equation, what must you do?

Mathematics

2 answers:

krek1111 [17]3 years ago

4 0

Answer:

You must divide by 3.

Step-by-step explanation:

3x / 3 = x

9 / 3 = 3

Hence x = 3

Drupady [299]3 years ago

4 0

Answer:

divide by 3 on both sides of the equation

Step-by-step explanation:

3x = 9

The variable x is being multiplied by 3. You want x alone, so you must use the opposite operation of multiplication to undo the multiplication by 3. The opposite of multiplication is is division. Since x is being multiplied by 3, you must divide by 3. The rule of equations is that you must do the same operation to both sides of the equation, so you must divide both sides of the equation by 3.

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Fill in the missing work and justification for step 2 when solving 3(x + 2) = 12.

liq [111]

Answer:

Step-by-step explanation:

3(x+2)=12

Distribute:

3x+6=12

Subtract:

3x+6-6=12-6

3x=6

Divide:

x=2

4 0

3 years ago

Solve the following equation algebraically:

Reptile [31]

Answer:

Step-by-step explanation:

divide by 3: x^2 = 4

Think you can finish that off now?

5 0

3 years ago

Please help find area !

11111nata11111 [884]

Answer:

33.32

Step-by-step explanation:

<h2><u>can use cross multiplication </u></h2>

20 : 34

19.6 : x

20x = 19.6 * 34

20x = 666.4

x= 666.4/20

x=33.32

4 0

3 years ago

Last year, a person wrote 126 checks. Let the random variable x represent the number of checks he wrote in one day, and assume

Arisa [49]

Answer: The mean number of checks written per day $=0.3452$

Standard deviation $=0.5875$

Variance $=0.3452$

Step-by-step explanation:

Given : The total number of checks wrote by person in a year = 126

Assume that the year is not a leap year.

Then 1 year = 365 days

Let the random variable x represent the number of checks he wrote in one day.

Then , the mean number of checks wrote by person each days id=s given by :-

$\lambda=\dfrac{126}{365}\approx0.3452$

Since , the distribution is Poisson distribution , then the variance must equal to the mean value i.e. $\sigma^2=\lambda=0.3452$

Standard deviation : $\sigma=\sqrt{0.3452}=0.5875372328\approx0.5875$

6 0

3 years ago

I need help with this answer?

Bumek [7]

Answer:

dont u have the answer

Step-by-step explanation:

7 0

3 years ago