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Dima020 [189]
3 years ago
12

Martin can travel 174 miles in 3 hours. at this rate, how far can he travel in 7 hours?

Mathematics
2 answers:
pickupchik [31]3 years ago
6 0

406 miles in 7 hours

Charra [1.4K]3 years ago
4 0
First we can find out how many miles he travels each hour.

# of miles he travels per hour = 174 miles / 3 hours
# of miles he travels per hour = 58 mph

He travels 7 hours so multiply the # of miles he travels per hour by 7.

58mph x 7h = 406 miles

Martin can travel 406 miles in 7 hours.
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(HELP ME ASAP PLEASE) In the following diagram, A || B.
vladimir1956 [14]

Answer:

m<6=77°

Step-by-step explanation:

Because the angles marked 3x+5 and 4x+7 are same side exterior angles, they are supplementary, meaning that

3x+5°+4x+7°=180°

7x+12°=180°

7x=168°

x=24°

Because the angles marked 6 and 3x+5 are corresponding angles, they are congruent, so:

<6=24*3+5

<6=77°

7 0
2 years ago
"Suppose an object falling in the atmosphere has mass m=15kg and the drag coefficient is γ=9kg/s. Recall that the differential e
Art [367]

Answer:

a. v(t)= -6.78e^{-16.33t} + 16.33 b. 16.33 m/s

Step-by-step explanation:

The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)=e^{\int\limits^  {}k \, dt } =e^{kt}. We now multiply both sides of the equation by the integrating factor.

μv' + μkv = μg ⇒ e^{kt}v' + ke^{kt}v = ge^{kt} ⇒ [ve^{kt}]' = ge^{kt}. Integrating, we have

∫ [ve^{kt}]' = ∫ge^{kt}

    ve^{kt} = \frac{g}{k}e^{kt} + c

    v(t)=   \frac{g}{k} + ce^{-kt}.

From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have

9.55 = 9.8 × 15/9 + ce^{-16.33 * 0} = 16.33 + c

       c = 9.55 -16.33 = -6.78.

So, v(t)=   16.33 - 6.78e^{-16.33t}. m/s = - 6.78e^{-16.33t} + 16.33 m/s

b. Velocity of object at time t = 0.5

At t = 0.5, v = - 6.78e^{-16.33 x 0.5} + 16.33 m/s = 16.328 m/s ≅ 16.33 m/s

6 0
3 years ago
The equation y=0.002x-0.20 can be used to determine the approximate profit,y in dollars,of producing x items.solve for x. How ma
lakkis [162]

Answer:

1966600 items must be produced in other to profit $3933

Step-by-step explanation:

from the equation y = 0.002x -0.20

where y is the profit in dollars

and x is the number of items

then to get the number of item to be produced in other to profit $3933 ?

will be by substituting $3933 for y in the equation and solving for x,

     3933 = 0.002x - 0.20

Firstly you will add 0.20 to both sides, which will be

      3933 + 0.20 = 0.002x - 0.20 + 0.20

       3933.20 = 0.002x

then we will divide both sides by 0.002

     3933.20 / 0.002 = 0.002x / 0.002

therefore, x = 1966600

5 0
3 years ago
About how many times greater is 12,000 miles than 3 • 10^3 miles?
Ad libitum [116K]

Answer:

3•10^3 is 3,000, so the answer is 9,000

8 0
4 years ago
Evaluate the expression for n=-3
satela [25.4K]

Answer:

5n is your answer hope this help

4 0
3 years ago
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