Question

Tell whether y= -3(x+1)^2+4 has a minimum value or a maximum value. Then find the value

Answer 1

Answer:

maximum value

Step-by-step explanation:

Given a parabola in vertex form

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

• If a > 0 then minimum value of k

• If a < 0 then maximum value at k

Given

y = - 3(x + 1)² + 4

a = - 3 < 0 ⇒ maximum value

The maximum value is the y- coordinate of the vertex

That is k, thus maximum value = 4