Answer:
Step-by-step explanation:
Given
square bottom area is 
Suppose x in. is cut from each corner to make a open box with maximum volume
New base area is 
Volume of box

Differentiate V w.r.t x to get maximum volume

Put 
![\left ( 24-x\right )\left [ -2x+24-x\right ]=0](https://tex.z-dn.net/?f=%5Cleft%20%28%2024-x%5Cright%20%29%5Cleft%20%5B%20-2x%2B24-x%5Cright%20%5D%3D0)
![\left ( 24-x\right )\left [ 24-3x\right ]=0](https://tex.z-dn.net/?f=%5Cleft%20%28%2024-x%5Cright%20%29%5Cleft%20%5B%2024-3x%5Cright%20%5D%3D0)

but x=24 is not possible therefore x=8 will yield maximum volume
Answer:
all done bud, I'm just here for the extra points :D
#4)
cross multiply
2(8x+10) = 4 * 5x
16x + 20 = 20x
4x = 20
x = 5