I need help with this question ?

Mathematics

1 answer:

algol133 years ago

3 0

All the expressions try to capture the initial value 4.05 and the common ratio 1/3.

At n=1 we need a_1 = 4.05; since stuff to the zeroth power is one, that's the first choice.

You might be interested in

Find the intercepts and graph each line.<br><br> a.) x – 4y =− 4<br> b.) 2x + 5y =-10

Snezhnost [94]

Answer:

(1,5) I think that's what it is

4 0

1 year ago

Please help I’m stuck.

madam [21]

Well the slope is -3 and I'm assuming that the y-intercept is 250 because that's where it touches it at all on the graph

Hope this helps. If it does, please rate it as Brainliest

3 0

3 years ago

X-4y-8=6/8+-8y-2y<br>5y-3(6-7/8)=5x-4y+3

Ivan

First simplify

x-4y-8=3/4-10y
add 10y both sides and add 8
x+6y=8+3/4
times 4 both sides
4x+24y=32+3
4x+24y=35

5y-3(6-7/8)=5x-4y+3
add 4y both sides
9y-3(6-7/8)=5x+3
distribute
9y-18+21/8=5x+3
minus 5x both sides
9y-5x-18+21/8=3
add 18 to both sides and minus 21/8 both sides
9y-5x=21-21/8
times 8 both sides
72y-40x=147
72y-40x=147

so we got

24y+4x=35
72y-40x=147

multiply first equation by -3 and add to 2nd

-72y-12x=-105
72y<span>-40x=147 +</span>
0y-52x=42

-52x=42
divide both sides by -52
x=-21/26
sub back

24y+4x=35
24y+4(-21/26)=35
using math
y=497/312

the solution is
$( \frac{-21}{26}, \frac{497}{312} )$

8 0

3 years ago

Solve 2x2 + 12x - 14 = 0 by completing the square

vovangra [49]

Answer:

Step-by-step explanation:

$(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\\\2x^2+12x-14=0\qquad\text{divide both sides by 2}\\\\x^2+6x-7=0\qquad\text{add 7 to both sides}\\\\x^2+2(x)(3)=7\qquad\text{add}\ 3^2=9\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=7+9\\\\(x+3)^2=16\Rightarrow x+3=\pm\sqrt{16}\\\\x+3=-4\ or\ x+3=4\qquad\text{subtract 3 from both sides}\\\\x=-7\ or\ x=1$

5 0

3 years ago

How to write this in radical form

Roman55 [17]

Ax/n= nsquare root a^x

5 0

3 years ago