What is the product simplest form stat any restrictions on the variable 3g^5/10h^2 x h^5/10g^2

1 answer:

6 0

The restriction are that neither h nor g may equal zero as that would lead to division by zero.

The simplification after units cancel is:

(3(gh)^3)/100 or if you prefer

0.03(gh)^3

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object weighs 8,000 grams, how many kilograms does it weigh? A) 8 kilograms B) 80 kilograms C) 800 kilograms D) 80,000 kilograms

givi [52]

Answer:

A) 8 kilograms

Step-by-step explanation:

"kilo-" is a prefix meaning 1000. So, 8 kilo-grams = 8 thousand grams = 8,000 grams.

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3 years ago

19 = -23+ 6(2 - p) Can someone please help me?!?!

lions [1.4K]

Step-by-step explanation:

19 = -23+ 6(2 - p)

19=-23+12-6p

19=-11-6p

6p=-11-19

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2 years ago

Read 2 more answers

WILL MARK BRAINLIEST what is the domain of (f/g) (x)?

tatyana61 [14]

Given that $f(x) = \sqrt{7-x}$ and $g(x) = \sqrt{x + 2}$ , we can say the following:

$\Bigg(\dfrac{f}{g}\Bigg)(x) = \dfrac{f (x)}{g(x)} = \dfrac{\sqrt{7 - x}}{\sqrt{x+2}}$

Now, remember what happens if we have a negative square root: it becomes an imaginary number. We don't want this, so we want to make sure whatever is under a square root is greater than 0 (given we are talking about real numbers only).

Thus, let's set what is under both square roots to be greater than 0:

$\sqrt{7 - x} \Rightarrow 7 - x \geq 0 \Rightarrow x \leq 7$

$\sqrt{x + 2} \Rightarrow x + 2 \geq 0 \Rightarrow x \geq -2$

Since both of the square roots are in the same function, we want to take the union of the domains of the individual square roots to find the domain of the overall function.

$x \leq 7 \,\,\cup x \geq -2 = \boxed{-2 \leq x \leq 7}$

Now, let's look back at the function entirely, which is:

$\Bigg( \dfrac{f}{g} \Bigg)(x) = \dfrac{\sqrt{7 - x}}{\sqrt{x+2}}$

Since $\sqrt{x + 2}$ is on the bottom of the fraction, we must say that $\sqrt{x + 2} \neq 0$ , since the denominator can't equal 0. Thus, we must exclude $\sqrt{x + 2} = 0 \Rightarrow x + 2 = 0 \Rightarrow x = -2$ from the domain.