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mario62 [17]
3 years ago
6

Can an acid-base indicator give you an exact value for the pH of a substance?

Chemistry
1 answer:
OlgaM077 [116]3 years ago
7 0
Yes and no it depends on what u r useing
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How could you safely determine if a base is stronger than an acid? Compare the taste of the base and the acid. Use a conductivit
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Use blue litmus paper. This is an indicator that can safely determine whether it is a base or an acid by changing color in response to the substance. This color indicates whether it is an acid or a base. Refer to the pH scale to see if the substance is basic or acidic.
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Which is an example of a bioresource used to build a home?
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The answer should be A.
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Which of the conservationists discussed earlier in this unit is
Arte-miy333 [17]

The correct answer is A. The conservationist credited with founding the Wilderness Society is Bob Marshall.

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6 0
2 years ago
Read 2 more answers
How much energy (in Joules) is required to convert 129 grams of ice at −23.0 °C to liquid water at 18.0 °C?
Karo-lina-s [1.5K]

Answer:

The energy that is required for the process is:

6230.7 J + 42957 J + 9715.2 J = <u>58902.9 joules</u>

Explanation:

This is a calorimetry problem:

Q = m . C . ΔT

Q = heat; m = mas; C is the specific heat and

ΔT = Final T° - Initial T°

Q = C lat . m

Q = Heat

m = mass

C lar = Latent heat of fusion

First of all we calculate the heat for ice, before it takes the melting point. (from -23°C  to 0°C)

Q = 129 g . 2.10 J/g°C . (0°C - (-23°C)

Q = 129 g . 2.10 J/g°C . 23°C → 6230.7 joules

Then, the ice has melted. To be melted and change the state it required:

Q = C lat . m

Q = 333 J/°C . 129 g → 42957 joules

And in the end, we have water that changed its T° from O°C to 18°C

Q = 129 g . 4.184 J/g °C . (18°C - 0°C)

Q = 9715.2 Joules

The energy that is required for the process is:

6230.7 J + 42957 J + 9715.2 J = 58902.9 joules

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Without constants you would not know which variable affected the
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Two independent variables could change at the same time, and you would not know which variable affected the dependent variable
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