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Burka [1]
3 years ago
6

Geometry and polarity of SnCl2

Chemistry
1 answer:
Natali5045456 [20]3 years ago
6 0

<span>Stannous Chloride, doesn't normally form molecules; two bonding pairs and one nonbonding pair on the dominant Sn; the bond angles are coarsely 109 degrees which is p2 hybridized. The molecule is considered polar because of the angular shape that it possess. </span>

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What is the name of an ideal-gas process in which no heat is transferred?.
PIT_PIT [208]

Answer:

Adiabatic. This is a process where no heat is being added or removed from the system. Or can be simply stated as: no heat transfer (or heat flow) happening in a system.

Explanation:

6 0
2 years ago
Why does silicon have a high melting point
Igoryamba
If the bonds are held together tightly, as an ionic bond or even a covalent bond, there will need to be a strong force to separate those bonds. This would by why their would be a high melting point. Another reason would be re-activity. <span />
7 0
3 years ago
Shown below is a table with plants and animals with their adaptations.
zhenek [66]

Answer:

Desert

Explanation:

The adaptation shown by the given plants and animals shows that they will adapted to the desert biome.

It is so because, due to high temperature of desert some desert animals like camel have the storage of fat in humps or tails; some animals have large ears such as Jackrabbits, it helps to release body heat and adapt in high temperature; plants have thick water holding tissues to reduce water loss in heat and waxy coating that keeps  the plants cooler and reduce moisture loss.

Hence, the correct answer is "Desert".

8 0
3 years ago
The ka of hf is 6.8 x 10-4. what is the ph of a 0.35 m solution of hf?
damaskus [11]
When the reaction equation is:

HF ↔ H+   +   F-

and when the Ka expression
= concentration of products/concentration of reactions

so, Ka = [H+][F-]/[HF]

when we assume:

[H+] = [F-] = X

and [HF] = 0.35 - X

So, by substitution:

6.8 x 10^-4 = X^2 / (0.35 - X) by solving for X

∴ X = 0.015 M

∴[H+] = X = 0.015

when PH = -㏒[H+]

∴PH = -㏒0.015

        = 1.8
6 0
3 years ago
What is the volume of 40g of sugar given it’s listed density
lora16 [44]

Answer:

25.157 cm³

Explanation:

Data Given:

Mass of Sugar (m) = 40g

Density of sugar given in literature = 1.59 g/cm³

Volume of Sugar = ?

The formula will be used is

                              d = m/v ........................................... (1)

where

D is density

m is the mass

v is the volume

So

Rearrange the Equation (1)

                              d x v = m

                               v = m/ d         ................................................ (2)

put the given values in Equation  (2)

                       v = 40g / 1.59 g/cm³

                       v = 25.157 cm³

volume of 40 g of sugar = 25.157 cm³

8 0
3 years ago
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