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3 years ago

How many grams of sodium chloride are present in a 0.75 M solution with a volume of 500.0 milliliters?

1 answer:

6 0

The units for molarity is moles of solute per liter of solution which means if you multiply the molarity of a solution by its volume you get how many moles of solute are in the solution. (0.75Mx0.5L=0.375mol NaCl) Then you can multiply the moles of sodium chloride (0.375 mol) by its molar mass (58.45 g/mol) to get 21.92g of sodium chloride. That means there is 21.92 grams of sodium chloride in 500mL of 0.75M solution. I hope this helps. Let me know if anything is unclear.

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In this case, the Boyle's is mathematically defined via:

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