1. a 2.b 3 a 4. c. 4.a 5. d 6.a. 2Na + Cl2 2NaC 7.c. 3 8.3 9.b
Molarity = moles / liter
a) M = 2/4 = 0.5 M
b) Moles = 4/(30 + 16 + 1)
= 0.085
M = 0.085 / 2 = 0.0425 M
c) Moles = 5.85 / (23 + 35.5)
= 0.1
M = 0.1 / 0.4
= 0.25 M
Answer:
109.09°C
Explanation:
Given that:
the capacity of the cooling car system = 5.6 gal
volume of solute = volume of the water; since a 50/50 blend of engine coolant and water (by volume) is used.
∴ 
Afterwards, the mass of the solute and the mass of the water can be determined as shown below:
mass of solute = 


On the other hand; the mass of water = 


Molarity = 
= 
= 17.757 m
≅ 17.76 m
∴ the boiling point of the solution is calculated using the boiling‑point elevation constant for water and the Molarity.

where,
= 0.512 °C/m
= 100°C + 17.56 × 0.512
= 109.09 °C
Answer:
47.3 ml
Explanation:
The graduated cylinder is shown in the image attached.
Now we have to take a good look at the cylinder, the lines between 45 and 50 are 46, 47, 48 and 49. Even though the points in between two lines weren't graduated but we can intelligently guess the correct volume by observing the upper meniscus of the liquid. Hence the answer.