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butalik [34]
3 years ago
12

Methanol, CH3OH, is the simplest of the alcohols. It is synthesized by the reaction of hydrogen and carbon monoxide. Write chemi

cal reactions. If 500 mol of CO and 750 mol of H2 are present, which is the limiting reactant?
Chemistry
1 answer:
Serhud [2]3 years ago
8 0

Answer:

The limiting reactant is H₂

Explanation:

The reaction of hydrogen (H₂) and carbon monoxide (CO) to produce methanol (CH₃OH) is the following:

2H₂(g) + CO(g) → CH₃OH(g)

From the balanced chemical equation, we can see that 1 mol of CO reacts wIth 2 moles of H₂. So, the stoichiometric ratio is:

2 mol H₂/1 mol CO = 2.0

We have 500 mol of CO and 750 mol of H₂, so we calculate the ratio to establish a comparison:

750 mol H₂/500 mol CO = 1.5

Since 2.0 > 1.5, we have fewer moles of H₂ than are needed to completely react with 500 moles of CO. In fact, we need 1000 moles of H₂ and we have 750 moles. So, the limiting reactant is H₂.

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How manymoles of each ion are present in 175 mL of 0.147 M Fe2(SO4)3?
lilavasa [31]

Answer: 0.0257 moles of Fe^{3+}  and 0.0257 moles of SO_4^{2-}

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{moles}{\text {Volume in L}}

moles of  Fe_2(SO_4)_3=Molarity\times {\text {Volume in L}}=0.147\times 0.175L=0.0257moles

The balanced reaction for dissociation will be:

Fe_2(SO_4)_3\rightarrow Fe^{3+}+SO_4^{2-}

According to stoichiometry:  

1 mole of Fe_2(SO_4)_3 gives 1 mole of Fe^{3+}  and 1 mole of SO_4^{2-}

Thus there will be 0.0257 moles of Fe^{3+}  and 0.0257 moles of SO_4^{2-}

8 0
3 years ago
The estimate obtained from a sample of which size is likely to be closest to
zubka84 [21]

The answer is C, 85.

8 0
3 years ago
Read 2 more answers
Calculate the molar solubility of CaF2 in a 0.25 m solution of NaF(aq).
Kipish [7]

Answer:

6.4 × 10^-10 M

Explanation:

The molar solubility of the ions in a compound can be calculated from the Ksp (solubility constant).

CaF2 will dissociate as follows:

CaF2 ⇌Ca2+ + 2F-

1 mole of Calcium ion (x)

2 moles of fluorine ion (2x)

NaF will also dissociate as follows:

NaF ⇌ Na+ + F-

Where Na+ = 0.25M

F- = 0.25M

The total concentration of fluoride ion in the solution is (2x + 0.25M), however, due to common ion effect i.e. 2x<0.25, 2x can be neglected. This means that concentration of fluoride ion will be 0.25M

Ksp = {Ca2+}{F-}^2

Ksp = {x}{0.25}^2

4.0 × 10^-11 = 0.25^2 × x

4.0 × 10^-11 = 0.0625x

x = 4.0 × 10^-11 ÷ 6.25 × 10^-2

x = 4/6.25 × 10^ (-11+2)

x = 0.64 × 10^-9

x = 6.4 × 10^-10

Therefore, the molar solubility of CaF2 in NaF solution is 6.4 × 10^-10M

8 0
3 years ago
In a solution, the solvent is...
Marina CMI [18]

Answer:

The solvent is the substance that dissolves solutes.

Explanation:

Solutes are the ones being dissolved. Examples could be sugar, salt, etc.

Solvents are the dissolver. Examples could be acids like HCl or water.

7 0
4 years ago
Read 2 more answers
If a helium filled ballon has a volume of 3.4l at 25°c and 1.18atm., what is its volume at STP?​
vladimir2022 [97]

Answer:

3.711 L

Explanation:

The formula you need to use is the following:

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\

3.4L / 298 K = V2 / 273 K

V2 = 3.711 L

5 0
2 years ago
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