In a recent election Corrine Brown received 13443 more votes than Bill Randall. If the total number of votes was 119289, find th
1 answer:
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As the question is unable to be understood/incomplete hence let's discuss the complete question (most probable question) and the answer for that.
Updated Question:
"A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test. Each adult bike requires 6 hours to build and 4 hours to test. With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week. If c represents child bikes and a represents adult bikes, determine which system of inequality best explains whether the company can build 20 child bikes and 6 adult bikes in the week. No, because the bike order does not meet the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100 No, because the bike order does not meet the restrictions of 4c + 4a ≤ 120 and 6c + 4a ≤ 100 Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100 Yes, because the bike order meets the restrictions of 4c + 4a ≤ 120 and 6c + 4a ≤ 100"
Answer:
Correct answer for this question is first option because it satisfies the first inequality but not the second one.
Step by Step Explanation:
<u>First Inequality:</u>
4(20)+6(6)≤120
80+36≤120
116≤120 ⇒ TRUE
<u>Second Inequality:</u>
4(20)+4(6)≤100
80+24≤100
104≤100 ⇒ FALSE
Answer:
A) P=2.28%
B) P=28.57%
C) I expect 10 students to be unable to complete the exam in the alloted time.
Step-by-step explanation:
In order to solve this problem, we will need to find the respective z-scores. The z-scores are found by using the following formula:
Where:
z= z-score
x= the value to normalize
= standard deviation
The z-score will help us find the area below the normal distribution curve, so in order to solve this problem we need to shade the area we need to find. (See attached picture)
A) First, we find the z-score for 60 minutes, so we get:
So now we look for the z-score on our normal distribution table. Be careful with the table you are using since some tables will find areas other than the area between the mean and the desired data. The table I used finds the area between the mean and the value to normalize.
so:
A=0.4772 for a z-score of -2
since we want to find the number of students that take less than 60 minutes, we subtract that decimal number from 0.5, so we get:
0.5-0.4772=0.0228
therefore the probability that a student finishes the exam in less than 60 minutes is:
P=2.28%
B) For this part of the problem, we find the z-score again, but this time for a time of 75 minutes:
and again we look for this z-score on the table so we get:
A=0.1915 for a z-score of -0.5
Now that we got this area we subtract it from the area we found for the 60 minutes, so we get:
0.4772-0.1915=0.2857
so there is a probability of P=28.57% of chances that the students will finish the test between 60 and 75 minutes.
C) Finally we find the z-score for a time of 90 minutes, so we get:
We look for this z-score on our table and we get that:
A=0.3413
since we need to find how many students will take longer than 90 minutes to finish the test, we subtract that number we just got from 0.5 so we get:
0.5-0.3413=0.1586
this means there is a 15.86% of probabilities a student will take longer than 90 minutes. Now, since we need to find how many of the 60 students will take longer than the 90 available minutes, then we need to multiply the total amount of students by the percentage we previously found, so we get:
60*0.1586=9.516
so approximately 10 Students will be unavailable to complete the exam in the allotted time.
