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3 years ago

A pack of 5 crackers has 205 calories how many calories in one cracker

Mathematics

2 answers:

mash [69]3 years ago

8 0

205/5=41

Each cracker has 41 calories

svp [43]3 years ago

4 0

Here you're finding a "unit measurement."

205 calories

--------------------- = 41 cal/cracker (answer)

5 crackers

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Can someone solve this?

aleksley [76]

Answer:

Considering the Law of Cosines:

$c^2=a^2+b^2-2ab*cosC$

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3 years ago

a group raised $276 for its favorite charity. this is 23% of the amount it hopes to raise. how much money does the group want to

OverLord2011 [107]

Answer: The group wants to raise $1,200.

Step-by-step explanation:

We can use a proportion to solve.

part/whole = percent/100

If we insert the values:

276/x = 23/100

We can cross multiply.

276 x 100 = 27,600

27,600 / 23 = 1,200

$1,200 is the answer.

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2 years ago

PLEASE HELP MATH QUESTION PIC BELOW

Vinil7 [7]

Answer:

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Step-by-step explanation:

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3 years ago

If I have (7x+3) degrees and (8x+1) degrees what would that equal

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Step-by-step explanation:

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3 years ago

A pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. The height, h, of th

Gennadij [26K]

<h2>Explanation:</h2>

In this problem we have a pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. So the height, h, of the pumpkin at time t seconds after the launch can be modeled by the equation:

$h(t) = -16t^2 + 84t + 20$

So this is the equation of a parabola. The maximum of this parabola occurs at its vertex. So let's find this vertex:

$\text{The x-value of the vertex is}: \\ \\ t=-\frac{b}{2a} \\ \\ \\ Where: \\ \\ a=-16 \\ \\ b=84 \\ \\ c=20 \\ \\ \\ t=-\frac{84}{2(-16)} \\ \\ t=-\frac{84}{-32} \\ \\ t=\frac{21}{8}=2.625 \\ \\ h(2.625)=-16(2.625)^2+84(2.625)+20 \\ \\ h(2.625)=-110.25+220.5+20 \\ \\ h(2.625)=130.25m$

Finally, the maximum occurs at time 2.625 seconds when the height is 130.25m

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3 years ago