A pack of 5 crackers has 205 calories how many calories in one cracker
2 answers:
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Answer:
≈ 23.4
Step-by-step explanation:
A = bh
270 = 15b
b = 18
Now you know the two legs, use the Pythagorean Theorem to find the value of the hypotenuse: a² + b² = c²
15² + 18² = c²
225 + 324 = c²
c² = 549
c = √549
The given expression is: 
So, there are two terms in the expression
1)
2) -5
The constant term is -5.
The co-efficient of is 4.
So, there are two terms in the expression
1)
2) -5
The constant term is -5.
The co-efficient of