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sineoko [7]
3 years ago
11

A pack of 5 crackers has 205 calories how many calories in one cracker

Mathematics
2 answers:
mash [69]3 years ago
8 0

205/5=41

Each cracker has 41 calories

svp [43]3 years ago
4 0

Here you're finding a "unit measurement."

205 calories

--------------------- = 41 cal/cracker (answer)

5 crackers

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Can someone solve this?
aleksley [76]

Answer:

Considering the Law of Cosines:

c^2=a^2+b^2-2ab*cosC

a=14mi; b=24mi; c=CA; C=91degrees

\cos \left(91^{\circ \:}\right)=-0.01745\dots

c^2=14^2+24^2-2(14)(24)*\cos \left(91^{\circ \:}\right)\\c^2=196+576-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*(-0.01745)\\c^2=772+11.7264\\c=\sqrt{772+11.7264} \\c=\sqrt{783.7264}\\c=27.99mi

4 0
3 years ago
a group raised $276 for its favorite charity. this is 23% of the amount it hopes to raise. how much money does the group want to
OverLord2011 [107]

Answer: The group wants to raise $1,200.

Step-by-step explanation:

We can use a proportion to solve.

part/whole = percent/100

If we insert the values:

276/x = 23/100

We can cross multiply.

276 x 100 = 27,600

27,600 / 23 = 1,200

$1,200 is the answer.

6 0
2 years ago
PLEASE HELP MATH QUESTION PIC BELOW
Vinil7 [7]

Answer:

∠MNP is your answer

Step-by-step explanation:

Note the angle and the order it is said. It is ∠ABC, which means the double line side, one curve line angle, and then triple line side.

Now look at the second triangle, the same double line side (NM), one curve line angle (∠N), and triple line side (NP)

Put them together: ∠MNP is your answer

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3 0
3 years ago
If I have (7x+3) degrees and (8x+1) degrees what would that equal
Sidana [21]

Answer:

180

Step-by-step explanation:

i just did it got it right

8 0
3 years ago
A pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. The height, h, of th
Gennadij [26K]
<h2>Explanation:</h2>

In this problem we have a pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. So the height, h, of the pumpkin at time t seconds after the launch can be modeled by the equation:

h(t) = -16t^2 + 84t + 20

So this is the equation of a parabola. The maximum of this parabola occurs at its vertex. So let's find this vertex:

\text{The x-value of the vertex is}: \\ \\ t=-\frac{b}{2a} \\ \\ \\ Where: \\ \\ a=-16 \\ \\ b=84 \\ \\ c=20 \\ \\ \\ t=-\frac{84}{2(-16)} \\ \\ t=-\frac{84}{-32} \\ \\ t=\frac{21}{8}=2.625 \\ \\ h(2.625)=-16(2.625)^2+84(2.625)+20 \\ \\ h(2.625)=-110.25+220.5+20 \\ \\ h(2.625)=130.25m

Finally, the maximum occurs at time 2.625 seconds when the height is 130.25m

8 0
3 years ago
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