Given that the line passes through two points
(-2,-2) and (x1,y1)
Equation in point slope form is
y-y1 = m(x-x1)
substitute for slope
Hence equation of the line = ![\frac{y2-y1}{x2-x1} =[tex]y-y1 = \frac{-2-y1}{-2-x1}(x-x1)](https://tex.z-dn.net/?f=%5Cfrac%7By2-y1%7D%7Bx2-x1%7D%20%3D%5Btex%5Dy-y1%20%3D%20%5Cfrac%7B-2-y1%7D%7B-2-x1%7D%28x-x1%29)
Since we donot know the value of x1or y1 the equation would contain x1, y1 also as answer.
Answer in point slope form is
Answer:
here you go , all four completed, took me some time , hipe i was able to help you out tho
Answer:
-21
Step-by-step explanation:
We are told to find f(x) + g(x) for x= -3. Therefore, we must evaluate f(-3) and g(-3), then add them together.
First, evaluate f(-3).
f(x)=4x-7
To find f(-3), we need to substitute -3 in for x.
f(-3)= 4(-3)-7
Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction First, multiply 4 and -3.
f(-3)= -12-7
Next, subtract 7 from -12
f(-3)= -19
Next, find g(-3).
g(x)=2x+4
To find g(-3), substitute -3 in for x.
g(-3)= 2(-3)+4
Solve according to PEMDAS. First, multiply 2 and -3.
g(-3)= -6+4
Next, add -6 and 4
g(-3)= -2
Now, we can add f(-3) and g(-3) together.
f(-3) + g(-3)
f(-3)= -19
g(-3)= -2
-19 + -2
Add
-21
I’ll get it correct here :)
He ate 19.95 grams of sugar.
3.5 x 5.7 = 19.95
