Consider three molecules, named X, Y, and Z. When added to a beaker of water they undergo spontaneous reactions. When X is added
to a fresh beaker of water a reaction converts X to Y and then another reaction converts Y to Z until all three are in equilibrium. Similarly, if Z is added to a fresh beaker a reaction converts Z to Y and then another reaction converts Y to X until all three are in equilibrium. You have a beaker of water with X, Y, and Z all in equilibrium. Choose the answer that best explains what will happen if you add more Y to the beaker. Reaction = X Y Z A .X will decrease / Z will increase
B. X will stay the same and Z stay the same
C. X will increase / Z will stay the same
D. X will stay the same / Z will increase
E. X will increase / Z will increase
Here in the question we can see that all the three compounds X Y and Z are in equilibrium as they are put in a water beaker containing water. This phenomenon is Called chemical equilibrium when the substances that are isomers to each other actually forms in water and their relative concentration remains in a particular ratio according to their stability.
Here in the question, the solution contains X Y and Z in equilibrium. But if more Y is added in the solution, firstly the equilibrium constant for X and Y will get disrupted because X will get low in amount with respect to Y. So some Y will get converted to X. Similarly, when Z will also face the same problem and some Y will get converted to Z. Hence the amounts of both X and Y will increase along with Y.
