Lead to more test and what you think about whatever your conclusion is about
<span>Chromosomal abnormalies effect all of the bodies cells. Certain anomolies effect different body parts in different ways. One anomily may effect the heart and the other vision or hearing. Hope this helps. Have a nice day. Feel free to ask more questions.</span>
I would pick H but it might be J but I am pretty sure it is H so go with that ok if you need any thing else I will help you ok
Answer:
1. Allele frequency of b = 0.09 (or 9%)
2. Allele frequency of B = 0.91 (0.91%)
3. Genotype frequency of BB = 0.8281 (or 82.81%)
4. Genotype frequency of Bb = 0.1638 (or 16.38%)
Explanation:
Given that:
p = the frequency of the dominant allele (represented here by B) = 0.91
q = the frequency of the recessive allele (represented here by b) = 0.09
For a population in genetic equilibrium:
p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)
(p + q)^2 = 1
Therefore:
p^2 + 2pq + q^2 = 1
in which:
p^2 = frequency of BB (homozygous dominant)
2pq = frequency of Bb (heterozygous)
q^2 = frequency of bb (homozygous recessive)
p^2 = 0.91^2 = 0.8281
2pq = 2(0.91)(0.9) = 0.1638
Given what we know, we can confirm that the tree with the fungi will be more likely to survive.
<h3>Why would this tree survive over the other one?</h3>
This has to do with the benefit from the symbiotic relationship established with the fungi. In exchange for nutrients to live, the fungi offer the tree protection from pathogens such as the one it is being injected with.
Therefore, we can confirm that the tree with the fungi will be more likely to survive.
To learn more about symbiotic relationships visit:
brainly.com/question/26741757?referrer=searchResults
