I don’t really know exactly to what degree you need to put in your solution. But I rounded to the nearest tenth degree.
A = 112 degrees
B= 28 degrees (180-112-40 bc all sides of a triangle must equal 180)
C= 40
a= 27.6 (this is the side opposite of angle A)
b= 14 (side opposite b)
c= 19.2 (side opposite c)
HOW TO SOLVE:
c= law of sines, so c/sin(40) = 14/sin(28), multiply both sides by sin(40) so c can be isolated and solved for. c = 14sin(40)/sin(28). Plug into calculator then get answer. c is approximately 19.2.
a = law of sines again, so a/sin(112) = 14/sin(28). Multiply both sides again by sin(112) then solve. a = 14sin(112)/sin(28). Calculator again. a is around 27.6
Answer:
Step-by-step explanation:
First do your x2-x1/y2-y1 to find slope, which is 0-3/7-13 = -3/-6 = 1/2
Then plug into point slope form (choose either point)
(y-13) = 1/2(x-0)
OR
(y-7) = 1/2(x-3)
Answer:
-1 every time
Step-by-step explanation:
Answer: Add like terms
Step-by-step explanation:
For example, you would add 6x and 5x to make 11x, but there other two numbers you would leave alone.
