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babunello [35]
4 years ago
9

Why was it not possible to increase the vertical scale by 0.5 each time ?

Mathematics
1 answer:
NNADVOKAT [17]4 years ago
8 0

Answer:nothings not possible my friend (impossible)

Step-by-step explanation:

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A sample of marble has a volume of 6 cm3 and a density of 2.76 g/cm3. What is its mass?
Alenkasestr [34]

To solve for the mass of a substance is to simply get the product of volume and density, that is:

mass = density * volume

 

So calculating for mass:

mass = (2.76 g / cm^3) * 6 cm^3

<span>mass = 16.56 g</span>

3 0
3 years ago
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Determine how many digits are to the right of the decimal point in the answer from multiplying: 0.3568 x 0.042
Svetllana [295]

multiply

0.3568 x 0.042 = 0.0149856 (remember to combine the amount of decimal point places before moving).

C: 7 is your answer

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8 0
4 years ago
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NEED HELP ASAP!!!!!!!
Mama L [17]

Answer:

1. Four thousand five hundred ten

2. 51.65 rounded to the nearest whole number is 52.

3. 2622 divided by 3 = 874

4. 6940 / 10^{2} = 69.4

5. 3/4 x 5 = 3.75 or 3\frac{3}{4}

6. (2 x 7) - (2 x 5) = 4

7. The area is \frac{6}{7}

8. 70 - (20-13) would probably work

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8 0
3 years ago
Find the limit, if it exists. (if an answer does not exist, enter dne.) lim (x, y) → (0, 0) x4 − 20y2 x2 + 10y2
Firdavs [7]
Traveling along the x-axis, we have

\displaystyle\lim_{(x,y)\to(0,0)}\frac{x^4-20y^2}{x^2+10y^2}=\lim_{x\to0}\frac{x^4}{x^2}=\lim_{x\to0}x^2=0

On the other hand, along the y-axis we get

\displaystyle\lim_{(x,y)\to(0,0)}\frac{x^4-20y^2}{x^2+10y^2}=\lim_{y\to0}\frac{-20y^2}{10y^2}=\lim_{y\to0}(-2)=-2

Therefore the limit doesn't exist.
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3 years ago
How to solve an equation with two different variables.
77julia77 [94]

Answer:

Step-by-step explanation:

Move the variables to different sides of the equation. This "substitution" metho d starts out by "solving for x" (or any other variable) in one of the ...

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