Did I do this correctly?

Mathematics

1 answer:

Rina8888 [55]3 years ago

8 0

Yes!
- you applied the distributive property
- combined like terms
- and answered the rest right!

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I need you to answer with a, b, c, d

solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

$\begin{gathered} ax^2+bx+c=0 \\ \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}$

For the given function:

$f(x)=2x^2-10x-3$ $x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}$ $x=\frac{10\pm\sqrt[]{100+24}}{4}$ $\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\ \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\ \end{gathered}$ $\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\ \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}$ $\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\ \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

Then, the zeros of the given quadratic function are:

$\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\ \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

Answer: Third option

8 0

1 year ago

3/5 is the same as 3.5<br> Is he correct?

Alexxx [7]

He is not correct because 3.5 is actually 3 and 1/2
not 3/5
hope that helps @:)

5 0

3 years ago

Read 2 more answers

Tina creates a dot plot using the match scores 3, 2, 4, 5, 2, 3, 1, 2, 1, and 5. Which of the following dot plots represents the

bogdanovich [222]

The answer is

B. A dot plot is shown with the title Match Scores. There are 2 dots over score 1, 3 dots over score 2, 2 dots over score 3, 1 dot over score 4, and 2 dots over score 5.

100% Verified!

Hope This Helps!:)