Answer:
Step-by-step explanation:
so to make infinite many solutions.. the lines have to be the same line... so the 1st equation would just be a multiple of the 2nd.... like 2x... like that..or even 1x.. counts.. so the exact same equation
1 => C
2 => A
3 => D
4 => E
5 =>B
2nd picture: No solution means the lines are parallel but not on top of as the last 5 equations were
6=> 5/4x -10 then a parallel line has the same slope but a different off set
so => 5/4x-5
7=> -8x + 12
so => -8x +1
8 => 4x + y = 7
y=-4x + 7
=> -4x +2
9=> sum of A+B=8 can A+B also be 10 NO!!! >:/ grrr if the 2nd set of numbers were C+D =10 then yes.. of course
10=> sum of A + B =8 can A-B also be 8 ? no
Answer: nothing i really dont know the answer
Step-by-step explanation:
Let

the length and

the width. By the ratio of the sides:

Now, we'll find the perimeter p. We'll use the formula below:

The area of a rectangle is

. Then:
Answer: B
Step-by-step explanation:
Answer:
125
Step-by-step explanation:
x + y = 5
We need to have x^3 and y^3 in the expression, so cube both sides.
(x + y)^3 = 5^3
Expand the left side.
(x + y)(x + y)^2 = 125
(x + y)(x^2 + 2xy + y^2) = 125
x^3 + 2x^2y + xy^2 + x^2y + 2xy^2 + y^3 = 125
x^3 + 3x^2y + 3xy^2 + y^3 = 125
Now we need to separate x^3 + y^3.
x^3 + y^3 + 3x^2y + 3xy^2 = 125
We need to turn 3x^2y + 3xy^2 into 15xy.
Factor the GCF, 3xy, out of 3x^2y + 3xy^2.
x^3 + y^3 + 3xy(x + y) = 125
We know that x + y = 5, so substitute x + y with 5.
x^3 + y^3 + 3xy(5) = 125
x^3 + y^3 + 15xy = 125
Answer: 125