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FromTheMoon [43]
3 years ago
10

Light propagating in the glass n1= 1.65 wall of an aquarium tank strikes the interior edge of the wall with incidence angle 19.0

degrees . What is the angle of refraction in the water?
Physics
1 answer:
jonny [76]3 years ago
3 0
We can solve this using Snell's Law which is represented by the equation:
sin θ₁ / sin θ₂ = n₂ / n₁

From the problem, we can substitute values and solve for the angle of refraction.
sin 19 / sin θ₂ = 1.65 / 1
θ₂ = 11.38°

The angle of refraction would be 11.38°.
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8 0
3 years ago
A european car manufacturer reports that the fuel efficiency of the new microcar is 28.5 km/l highway and 22.0 km/l city. what a
Studentka2010 [4]

We know that:

1 mile = 1.61 km

1 gal = 3.8 L

 

Therefore converting the fuel efficiency rates:

highway = (28.5 km/L) * (1 mile / 1.61 km) * (3.8 L / 1 gal) = 67.27 mile / gal

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4 0
3 years ago
A 2.5 kg steel gasoline tank can holds 20.0 L of gasoline when full. What is the average density (in Kg/m^3) of the full gas can
yarga [219]

Answer:

D=792.3\ kg/m^3

Explanation:

<u>Average Density </u>

The density of an object of mass m and volume V is

\displaystyle D=\frac{m}{V}

If we know the density and the volume occupied by the object, the mass can be computed as

m=D.V

The tank can hold 20 L of gasoline when full. Converting to cubic meters

V_g=20*0.001=0.02\ m^3

That's the volume of the gasoline it contains. Knowing the density of the gasoline, we get the mass of gasoline.

m_g=680*0.02=13.6\ kg

To know the total mass of both, we add the 2.5 kg of the tank

m=m_t+m_g=13.6+2.5=16.1\ kg

The volume of the tank is computed solving for V

\displaystyle V=\frac{m}{D}

\displaystyle V_t=\frac{2.5}{7800}=3.205\times 10^{-4}\ m^3

The total volume is

V=V_g+V_t=0.02+3.205\times 10^{-4}=0.0203\ m^3

The average density is

\displaystyle D=\frac{16.1}{0.0203}

\boxed{D=792.3\ kg/m^3}

7 0
3 years ago
the kinetic energy of an object with mass m moving with a velocity of 5 m/s is 25 j what will be its kinetic energy when its vel
Dmitriy789 [7]

Answer:

100 J, 225 J

Explanation:

The kinetic energy of an object is given by:

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is the velocity of the object

In this problem, the initial kinetic energy of the object is

K = 25 J

Then, the velocity is doubled, which means

v' = 2v

Therefore, the new kinetic energy will be

K'=\frac{1}{2}m(2v)^2 = 4(\frac{1}{2}mv^2)=4K

Therefore, the kinetic energy has quadrupled:

K' = 4(25)=100 J

Later, the velocity is tripled, which means

v'' = 3v

Therefore, the new kinetic energy will be

K''=\frac{1}{2}m(3v)^2 = 9(\frac{1}{2}mv^2)=9K

Therefore, the kinetic energy has increased by a factor of 9:

K' = 9(25)=225 J

4 0
3 years ago
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