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2 years ago

According to the octet rule, an atom with two electron shells is most stable when it contains eight

1 answer:

3 0

According to the octet rule, an atom with two electron shells is most stable when it contains eight electrons. The answer is letter B. All atoms wanted to attain a stable energy level equal to that of the noble gases. A noble gas is where all valence electrons in the valence shell is completely filled.

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A steel aircraft carrier is 370 m long when moving through the icy North Atlantic at a temperature of 2.0 °C. By how much does t

34kurt

Answer:

The carrier lengthen is 0.08436 m.

Explanation:

Given that,

Length = 370 m

Initial temperature = 2.0°C

Final temperature = 21°C

We need to calculate the change temperature

Using formula of change of temperature

$\Delta T=T_{f}-T_{i}$

$\Delta T=21-2.0$

$\Delta T=19^{\circ}C$

We need to calculate the carrier lengthen

Using formula of length

$\Delta L=\alpha_{steel}\times L_{0}\times\Delta T$

Put the value into the formula

$\Delta L=1.2\times10^{-5}\times370\times19$

$\Delta L=0.08436\ m$

Hence, The carrier lengthen is 0.08436 m.

8 0

2 years ago

What is the wavenumber of the stretching vibrational mode for the CO molecule, given that the force constant of the bond is 680

Gnesinka [82]

Answer:

1.10134 * 10⁻⁹m⁻¹

Explanation:

K = 680Nm⁻¹

μ = ?

μ = (m₁ + m₂) / m₁m₂

compound = CO

C = 12.0 g/mol = 0.012kg/mol

O = 16.0g/mol = 0.016kg/mol

μ = (m₁ + m₂) / m₁m₂

μ = (0.012 + 0.016) / (0.012*0.016) = 145.83

v = 1/2πc * √(k/μ)

ν = 1/ 2*3.142* 3.0*10⁸ * √(630/145.83)

v = 5.30*10⁻¹⁰ * 2.078

v = 1.10134*10⁻⁹m⁻¹

8 0

3 years ago

Darina [25.2K]

Resolving vectors question. See diagram enclosed.

4 0

2 years ago

How much power is needed to lift the 200-N object to a height of 4 m in 4 s?

Vitek1552 [10]

Answer: 2000 watts

Explanation:

Given that,

power = ?

Weight of object = 200-N

height = 4 m

Time = 4 s

Power is the rate of work done per unit time i.e Power is simply obtained by dividing work by time. Its unit is watts.

i.e Power = work / time

(since work = force x distance, and weight is the force acting on the object due to gravity)

Then, Power = (weight x distance) / time

Power = (200N x 4m) / 4s

Power = 8000Nm / 4s

Power = 2000 watts

Thus, 2000 watts of power is needed to lift the object.

3 0

3 years ago

A 500 kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 30 N/m. The blo

m_a_m_a [10]

Answer:

x = 0.396 m

Explanation:

The best way to solve this problem is to divide it into two parts: one for the clash of the putty with the block and another when the system (putty + block) compresses it is spring

Data the putty has a mass m1 and velocity vo1, the block has a mass m2 . t's start using the moment to find the system speed.

Let's form a system consisting of putty and block; For this system the forces during the crash are internal and the moment is preserved. Let's write the moment before the crash

p₀ = m1 v₀₁

Moment after shock

$p_{f}$ = (m1 + m2) $v_{f}$

p₀ = $p_{f}$

m1 v₀₁ = (m1 + m2) $v_{f}$

$v_{f}$ = v₀₁ m1 / (m1 + m2)

$v_{f}$ = 4.4 600 / (600 + 500)

$v_{f}$ = 2.4 m / s

With this speed the putty + block system compresses the spring, let's use energy conservation for this second part, write the mechanical energy before and after compressing the spring

Before compressing the spring

Em₀ = K = ½ (m1 + m2) $v_{f}$ ²

After compressing the spring

$E_{mf}$ = Ke = ½ k x²

As there is no rubbing the energy is conserved

Em₀ = $E_{mf}$

½ (m1 + m2) $v_{f}$ ² = = ½ k x²

x = $v_{f}$ √ (k / (m1 + m2))

x = 2.4 √ (11/3000)

x = 0.396 m

7 0

3 years ago