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lord [1]
3 years ago
15

The largest water tower in Camden holds 2,000,000-gallons at 24 meters in the air.

Physics
1 answer:
DaniilM [7]3 years ago
8 0

Answer:

Explanation:

Given that,

The Camden holds a volume of

V = 2,000,000 gallons

At a height of

h = 24 m

We want to find the potential energy.

And potential energy can be calculated using

P.E = mgh

Where

m is the mass

g Is the acceleration due to gravity

h Is the height.

Given that,

Then volume is

V = 2,000,000 gallons

From research.

1 gallon ≈ 3.785 kg

Then,

2,000,000 gallons = 2,000,000 × 3.785 kg

So,

P.E = mgh

P.E = 2,000,000 × 3.785 × 9.81 × 24

P.E = 1.782 × 10^9 J.

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The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as , where a
Misha Larkins [42]

Answer:

3 times louder

Explanation:

The Loudness in decibel Db  L = 10㏒(I/I₀)  where I = sound intensity level and I₀ = threshold of hearing = 10⁻¹² W/m².

Now, for Jessica, I₁ = sound intensity level of Jessica's music = 10⁻⁹

and I₂ = sound intensity level of Braylee's music = 10⁻³

So, substituting the variables into the equation, we have

L₁ = 10㏒(I₁/I₀)

L₁ = 10㏒(10⁻⁹/10⁻¹²)

L₁ = 10㏒(10³)

L₁ = 3 × 10㏒10

L₁ = 30㏒10

L₁ = 30 dB

Now, for Braylee, I₂ = sound intensity level of Braylee's music = 10⁻³

So, substituting the variables into the equation, we have

L₂ = 10㏒(I₁/I₀)

L₂ = 10㏒(10⁻³/10⁻¹²)

L₂ = 10㏒(10⁹)

L₂ = 9 × 10㏒10

L₂ =90㏒10

L₂ = 90 dB

So, the number of times Braylee's music is louder than Jessica's music is L₂/L₁ = 90 dB/30 dB = 3

So, Braylee's music is 3 times louder than Jessica's music

6 0
3 years ago
By quadrupling the mass of the body hanging on the thread what will become the period of oscillation?​
nikklg [1K]

Well, the tension in the thread will probably quadruple, but the hanging body will continue to just hang there.  

The question gives us no evidence that it is doing any oscillating, and there's no reason for it to start just because it suddenly got heavier.

6 0
3 years ago
In a double-slit experiment, light from two monochromatic light sources passes through the same double slit. The light from the
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Answer:

\lambda_2 = 573.3 nm

Explanation:

As we know that the position of maximum intensity on the screen is given as

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here we know that

\lambda = wavelength

L = distance of the screen

d = distance between two slits

now we know that the position of 8th maximum intensity is same as that of 9th maximum on the screen

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\frac{N_1\lambda_1 L}{d} = \frac{N_2 \lambda_2 L}{d}

so here we have

8 (645 nm) = 9 \lambda_2

\lambda_2 = 573.3 nm

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3 years ago
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Answer:

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