The observable universe<span> is a spherical region of the </span>Universe, <span>comprising all matter that can be observed from Earth at the present time, because light and other signals from these objects have had time to reach Earth since the beginning of the cosmological expansion.
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Answer:
Option 10. 169.118 J/KgºC
Explanation:
From the question given above, the following data were obtained:
Change in temperature (ΔT) = 20 °C
Heat (Q) absorbed = 1.61 KJ
Mass of metal bar = 476 g
Specific heat capacity (C) of metal bar =?
Next, we shall convert 1.61 KJ to joule (J). This can be obtained as follow:
1 kJ = 1000 J
Therefore,
1.61 KJ = 1.61 KJ × 1000 J / 1 kJ
1.61 KJ = 1610 J
Next, we shall convert 476 g to Kg. This can be obtained as follow:
1000 g = 1 Kg
Therefore,
476 g = 476 g × 1 Kg / 1000 g
476 g = 0.476 Kg
Finally, we shall determine the specific heat capacity of the metal bar. This can be obtained as follow:
Change in temperature (ΔT) = 20 °C
Heat (Q) absorbed = 1610 J
Mass of metal bar = 0.476 Kg
Specific heat capacity (C) of metal bar =?
Q = MCΔT
1610 = 0.476 × C × 20
1610 = 9.52 × C
Divide both side by 9.52
C = 1610 / 9.52
C = 169.118 J/KgºC
Thus, the specific heat capacity of the metal bar is 169.118 J/KgºC
Answer:
Since the area of the perfect square is 11650, and all of a squares sides ar equal, we just need to find the square root.
The square root of 11650 is 107.935166.
One side of the square is 107.935166
107.935166 x 107.935166 = 11650
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When minerals are exposed to high pressure and temperatures, the individual minerals begin to realign themselves
Answer:
5 m
Explanation:
From the question,
v = λf....................... Equation 1
Where v = speed of the sound wave, λ = wavelength of the sound wave, f = frequency of the sound wave.
make λ the subject of the equation
λ = v/f..................... Equation 2
Given: v = 150 cm/s = 1.5 m/s, f = 0.3 hz.
Substitute these values into equation 2
λ = 1.5/0.3
λ = 5 m.
= 16 m/s