Answer:
22 and 46
Step-by-step explanation:
let
one number is x
another is 2x+2
now 2x+2+x=68
or, 3x+2=68
3x=66
or x=66/3=22
so one number is 22 and another is (22X2+2)=46
<u>Answer</u>
0
<u>Explanation</u>
(2m)/(2m+3)-(2m)/(2m-3)=1
Simplifying the left hand first
(2m)/(2m+3)-(2m)/(2m-3) = {2m(2m-3) - 2m(2m+3)}/(4m²-9)
(4m²-6m-4m²-6m)/(4m²-9)
= (-12m) / (4m²-9)
Now this equet to 1
(-12m) / (4m²-9) = 1
-12m = 4m²-9
4m²+ 12m -9 =0 ⇒⇒⇒ This is a quadratic equation that has 2 real solutions.
4m²+ 12m -9 =0
m² + 3m + (3/2)²= 9/4 + 9/4
(m + 3/2)² = 18/4
m = √18/2 - 3/2 or m = -√18/2 - 3/2
= 0.621 = -3.621
So we can say that the equation has NO extraneous solutions.
Answer = 0
Answer:
w^2 + 5w = 300
Step-by-step explanation:
A= length x width
A =300
Width = w
length = w + 5
Therefore
300 = (w) x (w + 5)
300 = w^2 + 5w
w^2 + 5w = 300
10I^2/3
This is the answer
