All categories

3 years ago

Triangles and angles Pls help

Mathematics

1 answer:

AleksandrR [38]3 years ago

4 0

Answer:

The two bottom angles of this triangle are both represented by the same variable, in this case, an x. This means, that both of the bottom angles are equal to each other.

So we have:

32 + x + x = 180 (since the TOTAL angles of a triangle adds up to 180)

32 + 2x = 180 (combine the 2 x's together)

2x = 148 (subtract a 32 from both sides)

x = 74

Let me know if this helps!

You might be interested in

The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2 : 3, what is the rati

Ksivusya [100]

<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

$\dfrac{24}{25}$

<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

$Perimeter\ of\ R=2(2x+3x)$

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

$Perimeter=2(L+B)$ )

Hence, we get:

$Perimeter\ of\ R=2(5x)$

i.e.

$Perimeter\ of\ R=10x$

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

$\text{Perimeter\ of\ square}=4s$

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

$4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}$

Now, we know that the area of a square is given by:

$\text{Area\ of\ square}=s^2$

and

$\text{Area\ of\ Rectangle}=L\times B$

Hence, we get:

$\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}$

and

$\text{Area\ of\ Rectangle}=2x\times 3x$

i.e.

$\text{Area\ of\ Rectangle}=6x^2$

Hence,

Ratio of the area of region R to the area of region S is:

$=\dfrac{6x^2}{\dfrac{25x^2}{4}}\\\\=\dfrac{6x^2\times 4}{25x^2}\\\\=\dfrac{24}{25}$

6 0

3 years ago

Read 2 more answers

You’ve probably heard police officers on television repeat the same line every single time they arrest someone: “You have the ri

djverab [1.8K]

Answer:

i think its d

4 0

3 years ago

Read 2 more answers

Mikaela placed a frame around a print that measures 10 inches by 10 inches. The area of just the frame itself is 69 square inche

olchik [2.2K]

Answer:

1.5 in

Step-by-step explanation:

Let x be the width of the frame.

Side of print=10 in

Area of frame=69 square in

We have to find the width of the frame.

Side of frame=10+x+x=10+2x

Area of square= $(side)^2$

By using the formula

Area of print= $10\times 10=100in^2$

Area of frame with print= $(10+2x)^2$

Area of frame=Area of frame with print-Area of print

$69=(10+2x)^2-100$

$(10+2x)^2=69+100=169$

$(10+2x)=\sqrt{169}=\pm 13$

$10+2x=13$

Because Side is always positive.

$2x=13-10=3$

$x=\frac{3}{2}=1.5$

Hence, width of frame=1.5 in

3 0

3 years ago

Math... find angle x...

choli [55]

Value of x is 76°

<u> </u><u>Step-by-step explanation:</u>

Given :- ∠JIH = 107°

and, JDI = 31°

To find :- value of x

solution:- ∠JIH + ∠JID =180° (the sum of angles on a line are supplementary)

∠JID = 180° - 107°

∠JID = 73°

Now in ΔJID

∠JID = 73° and ∠JDI = 31°

by angle some property of Δ

so, ∠JDI + ∠JID + ∠DJI = 180°

= 31° + 73° + ∠DJI = 180°

= 104° + ∠DJI = 180°

∠DJI = 180° - 104°

∠DJI = 76°

now, ∠DJI = ∠AJF = ∠X

so, x = 76°

hence value of x is 76°

8 0

3 years ago

HELP ME PLEASEEE !!!!!!!

Sindrei [870]

And it is also too small

5 0

3 years ago