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3 years ago

Help ASAP The ratio of two side lengths for the triangle given.Solve the variable.

Mathematics

1 answer:

Andreyy893 years ago

3 0

Answer:

a = 3

Step-by-step explanation:

AB/AC = 7/8 = 14a/48

7/8 = 14a/48

Multiply both sides by 8.

7 = 14a/6

Multiply both sides by 6 and switch sides.

14a = 42

a = 3

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Númer 9 and 10 please help

vredina [299]

9. -1,07, 1/2. 3........it is all I could see

10. -V25= -5
-5, -4,3, 0, V15, 4,2

8 0

2 years ago

Jacinta scores 23, 19, and 27 on three of her four tests. She wants to get an

pochemuha

Answer:

23+19+27+x = 96

x > 27

not sure if the answer can be left that way or do you assume that test results are whole numbers, if so then the answer would b=have to be 28.. but I think that >27 is the answer expected

Step-by-step explanation:

7 0

3 years ago

Determine what must be multiplied so that the expression below will have a common denominator. Use the backslash / to type in a

Mashutka [201]

Answer:

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

Step-by-step explanation:

Given

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Required

Make the denominator equal

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Factorize the denominator

$\frac{4}{x^2 - 4^2} + \frac{3}{x^2 + 4x + 4x+ 16}$

$\frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)}$

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

$\frac{x+4}{x+4} * \frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)} * \frac{x-4}{x-4}$

$\frac{4(x + 4)}{(x - 4)(x + 4)(x + 4)} + \frac{3(x - 4)}{(x+ 4)(x + 4)(x - 4))}$

$\frac{4(x + 4)}{(x^2 - 16)(x + 4)} + \frac{3(x - 4)}{(x^2 - 16)(x + 4))}$

<em>The expression now have the same denominator</em>

7 0

3 years ago

What is the product of ( x ^ ( 2 ) )/( 6 y );( 2 x )/( y ^ ( 2 ) ) and ( 3 v ^ ( 3 ) )/( 4 x );x \neq 0;y \neq 0

BabaBlast [244]

Answer:

i couldnt answer please be more specific

Step-by-step explanation:

5 0

2 years ago

Tanisha, Elicia, and Ajua are cousins. Tanisha is twice as old as Ajua, and Elicia is two years older than Tanisha. The sum of a

AfilCa [17]

Answer:

Step-by-step explanation:

Tanisha, Elicia, and Ajua are cousins. Tanisha is twice as old as Ajua, and Elicia is two years older than Tanisha. The sum of all their ages is 37. Use variable expressions and calculate the age of each girl

Let us represent:

The age of :

Tanisha = a

Elicia = b

Ajua = c

Tanisha, Elicia, and Ajua are cousins. Tanisha is twice as old as Ajua

a = 2c

c = 2/a

Elicia is two years older than Tanisha.l

b = a + 2

The sum of all their ages is 37.

a + b + c = 37

We substitute

a + a + 2 + 2/a = 37

2a + 2 + 2/a = 37

Use variable expressions and calculate the age of each girl

8 0

3 years ago