3 years ago

PLEASE HELP I'M MARKING BRAINLIEST!!!!!!

Mathematics

1 answer:

CaHeK987 [17]3 years ago

4 0

Answer:

download Gauthnath and see answer

You might be interested in

The slope of a line is -4, and the y-intercept is -3. What is the equation of the line written in slope-intercept form?

skad [1K]

The slope/intercept form of the equation of a straight line is

Y = (slope) X + (y-intercept) .

You know the slope and the y-intercept.
All you have to do is take that equation and fillum in.

6 0

4 years ago

Read 2 more answers

Jessica fills a cube shaped tank that has an edge of 70 cm with water from a tap. Water flows into the tank at a rate of 7L per

daser333 [38]

The volume of the tank is (70 cm)³ = 343,000 cm³.

Now,

1 mL = 1 cm³

1 L = 1000 mL

so we convert the given rate to

$\dfrac{7\,\rm L}{1\,\rm min} \cdot \dfrac{1000\,\rm mL}{1\,\rm L} \cdot \dfrac{1\,\mathrm{cm}^3}{1\,\rm mL} = \dfrac{7000\,\mathrm{cm}^3}{1\,\rm min}$

Then the time it will take to fill up the tank is

$343,000\,\mathrm{cm}^3 \cdot \dfrac{1\,\rm min}{7000\,\mathrm{cm}^3} = \boxed{49\,\rm min}$

6 0

2 years ago

Find the radius and diameter of a frisbee with a circumference of 11 pi inches.

nikdorinn [45]

Circumerence=2pir or dpi were r=radius and d=diameter
11pi=2pir
divid eobt sides by pi
11=2r
dvide 2
5.5=r

11pi=dpi
divide both sides by pi
11=d

diameter=11in
radius=5.5 in

6 0

4 years ago

A diameter of a truck is 56.5 what is the circustance of the wheel

Nadya [2.5K]

Answer:

I dont think I can help you without the rest of the question

Step-by-step explanation:

4 0

3 years ago

Regard y as the independent variable and x as the dependent variable and use implicit differentiation to find dx/dy. x3y2 − x4y

Flauer [41]

$\bf x^3y^2-x^4y=4xy^3=0\\\\
-------------------------------\\\\
\left( 3x^2y^2+x^32y\frac{dy}{dx} \right)-\left( 4x^3y+x^4\frac{dy}{dx} \right)+4\left( 1\cdot y^3+x3y^2\frac{dy}{dx} \right)=0
\\\\\\
2x^3y\frac{dy}{dx}-x^4\frac{dy}{dx}+12xy^2\frac{dy}{dx}=4x^3y-3x^2y^2-4y^3
\\\\\\
\cfrac{dy}{dx}\left( 2x^3y-x^4+12xy^2 \right)=4x^3y-3x^2y^2-4y^3
\\\\\\
\cfrac{dy}{dx}=\cfrac{4x^3y-3x^2y^2-4y^3}{2x^3y-x^4+12xy^2}$

7 0

3 years ago