Correct answer is: distance from D to AB is 6cm
Solution:-
Let us assume E is the altitude drawn from D to AB.
Given that m∠ACB=120° and ABC is isosceles which means
m∠ABC=m∠BAC = ![\frac{180-120}{2}=30](https://tex.z-dn.net/?f=%5Cfrac%7B180-120%7D%7B2%7D%3D30)
And AC= BC
Let AC=BC=x
Then from ΔACD , cos(∠ACD) = ![\frac{DC}{AC} =\frac{4}{x}](https://tex.z-dn.net/?f=%5Cfrac%7BDC%7D%7BAC%7D%20%3D%5Cfrac%7B4%7D%7Bx%7D)
Since DCB is a straight line m∠ACD+m∠ACB =180
m∠ACD = 180-m∠ACB = 60
Hence ![cos(60)=\frac{4}{x}](https://tex.z-dn.net/?f=cos%2860%29%3D%5Cfrac%7B4%7D%7Bx%7D)
![x=\frac{4}{cos60}= 8](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B4%7D%7Bcos60%7D%3D%208)
Now let us consider ΔBDE, sin(∠DBE) = ![\frac{DE}{DB} =\frac{DE}{DA+AB} = \frac{DE}{4+8}](https://tex.z-dn.net/?f=%5Cfrac%7BDE%7D%7BDB%7D%20%3D%5Cfrac%7BDE%7D%7BDA%2BAB%7D%20%3D%20%5Cfrac%7BDE%7D%7B4%2B8%7D)
![DE = 12sin(30) = 6cm](https://tex.z-dn.net/?f=DE%20%3D%2012sin%2830%29%20%3D%206cm)
The inverse of 2/3
is 3/2.
Good Luck! :)
Answer:
The answer is 445,446
Step-by-step explanation:
have a great day everyone :)
Answer:
9Kg, 18Kg and 63 Kg
Step-by-step explanation:
Sum the parts of the ratio, 1 + 2 + 7 = 10 parts
Divide the weight of sand by 10 to find the value of one part of the ratio
90 Kg ÷ 10 = 9 Kg ← value of 1 part of the ratio, thus
2 parts = 2 × 9 Kg = 18 Kg
7 parts = 7 × 9 Kg = 63 Kg
Thus the weights of each bag are 9 Kg, 18 Kg and 63 Kg
Answer:
133.33 mph
Step-by-step explanation:
The small trick is to notice the time. Is it 8:00 AM the same day. We don't know, but we will assume it is.
So the truck was on the road for 2 hours.
The car was on the road for 2 - 1/2 = 1 1/2 = 1.5 hours.
The distance travelled was 200 miles
Solution
d = r * t
200 = r * 1.5
200/1.5 = r
r = 133.33 miles / hour
The noise you hear is a siren trying to catch up to the car.