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3 years ago

10 faces and 12 vertices,how many edges does it have?

Mathematics

1 answer:

MArishka [77]3 years ago

6 0

The answer is 12 edges :)

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말 8.) A baker is ordering eggs for the week. How many cartons of 6 eggs would a baker need to have 225 eggs all together? Explai

morpeh [17]

Answer:

Step-by-step explanation:

We know that each carton contains 6 eggs and we need a total of 225. To find this answer, divide 225 by 6, which is 37.5. We would have to round up one because you cannot buy half of a carton. So the answer is 38 cartons.

6 0

3 years ago

Jim earned $700 this week. This was $20 less than four times the amount he earned last week. Which equation, when solved for x,

joja [24]

Answer: Your answer is d because if you solve for x you will get 180 and if you plug 180 into the equation it equals 700.

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3 years ago

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Calculate the vapor pressure (in torr) of a solution containing 0.2 moles of solute dissolved in 10 moles of water at 25°C. Vapo

Gnesinka [82]

Answer:

the vapor pressure of a solution at 25°C that contains 76.6 g of glucose (180.2 g/mole) in 250.0 mL of water. The vapor pressure of pure water at 25°C

Step-by-step explanation:

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3 years ago

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Solve for x in the triangle. Round your answer to the nearest tenth.<br> 13<br> 32°

zloy xaker [14]

Answer:

6.9

Step-by-step explanation:

imagine a circle with the center being the point with the 32 degree angle, and with the radius 13.

then

x = sin(32)×13 = 6.9 (6.88895...)

5 0

3 years ago

Given the vectors A⃗ and B⃗ shown in the figure ((Figure 1) ), determine the magnitude of B⃗ −A⃗. A is 28 degrees above the posi

Vlad [161]

This problem is represented in the Figure below. So, we can find the components of each vector as follows:

$\bullet \ cos(28^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{A_{x}}{44} \\ \\ \therefore A_{x}=44cos(28^{\circ})=38.85m \\ \\ \\ \bullet \ sin(28^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{A_{y}}{44} \\ \\ \therefore A_{y}=44sin(28^{\circ})=20.65m$

$\bullet \ cos(56^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{-B_{x}}{26.5} \\ \\ \therefore B_{x}=-26.5cos(56^{\circ})=-14.81m \\ \\ \\ \bullet \ sin(56^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{B_{y}}{26.5} \\ \\ \therefore B_{y}=26.5sin(56^{\circ})=21.97m$

Therefore:

$\vec{A}=(38.85, 20.65)m \\ \\ \vec{B}=(-14.81, 21.97)m$

So:

$\vec{B}-\vec{A}=(-14.81, 21.97)-(38.85, 20.65)=(-53.66,1.32)$

Finally, the magnitude is:

$\boxed{\left| \vec{B}-\vec{A}\right|=\sqrt{(-53.66)^2+(1.32)^2}=53.67m}$

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3 years ago

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