20 x 42= 840
So the area would be 840 mm^2.
Answer:
13% is less than 3/20.
Step-by-step explanation:
3/20 = .15
2/11 = .18(repeating)
1/6 = 1.6(repeating)7
13% = .13
and then .15
Using the information given, it is found that the class width for this frequency distribution table is of 1.
In this problem, these following classes are given:
0 – 1 14
2 – 3 1
4 – 5 8
6 – 7 12
8 – 9 12
The classes not given, which are 1 - 2, 3 - 4 and 5 - 6, have values of 0.
The <u>difference between the bounds of the classes is of 1</u>, thus, the class width is of 1.
A similar problem is given at brainly.com/question/24701109
Answer:
56.4°
Step-by-step explanation:
Let θ = the angle of elevation. Then
tanθ = 199/132 = 1.508
θ = arctan1.508
θ = 56.4°
The angle of elevation is 56.4°.
The equation is false because the real answer is z5/4. The variable doesn't just disappear.
