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3 years ago

Which expression is equivalent to 5 to the power3

Mathematics

2 answers:

shtirl [24]3 years ago

7 0

Answer:

=125

Step-by-step explanation:

11111nata11111 [884]3 years ago

4 0

Answer:

What are the given expressions??

Step-by-step explanation:

Since I can't see you're options, I'll just give you an answer that'll hopefully help...

5³ = 125

Hope that helps you!! :)

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HURRY plzz Identify to corresponding side to side HG.

a_sh-v [17]

Answer:

it would be EC (B)

Step-by-step explanation:

5 0

3 years ago

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Solve for x Show your work

telo118 [61]

Answer:

x = 12

Step-by-step explanation:

To solve this and show your work, you have to start of with the equation (3x - 6) = 30.

You then have to add 6 to both sides like this:

$(3x - 6) = 30 \\ \: \: \: \: \: \: \: \: \: \: + 6 \: \: \: \: \: + 6$

So then the 6 is cancelled out, and you are left with

3x = 36.

Now you just have to divide both sides by 3 like this:

$\frac{3x}{3} = \frac{36}{3}$

Which cancels 3 out, and you are left with

x = 12.

4 0

3 years ago

Find the linear approximation of the function f(x, y, z) = x2 + y2 + z2 at (4, 4, 7) and use it to approximate the number 4.022

miss Akunina [59]

Answer:

80.66

Step-by-step explanation:

$L\left( x \right) = f\left( a \right) + f'\left( a \right)\left( {x - a} \right)$

$f(x, y, z) = x^2+y^2+z^2$

Since we have three variables,

$L(x, y,z) = f(a, b,c) + f_x (a, b,c) (x - a) + f_y (a, b,c) (y - b) +f_z(a,b,c)(z-c)$

$f(4, 4, 7) = 4^2+4^2+7^2=81$

$f_x (a, b,c)=2x=2*4=8\\f_y (a, b,c)=2y=2*4=8\\ f_z(a,b,c)=2z=2*7=14$

Therefore:

$L(x, y,z) = 81+ 8(x - 4) + 8 (y - 4) +14(z-7)$

Using the above:

f(4.02, 3.99, 6.97) =81+ 8(4.02 - 4) + 8 (3.99 - 4) +14(6.97-7)=80.66.

The approximation of $4.02^2 + 3.99^2 + 6.97^2$ is 80.66000.

3 0

3 years ago

7y-3x= -5 solve for x

nika2105 [10]

7y - 3x = -5
-3x = -7y - 5
x = 7/3y + 5/3

7 0

3 years ago

The product of (4z^2 + 7z - 8) and (-z + 3) is -4z^3 + xz^2 + yz - 24. What is the value of x? What is the value of y?

ycow [4]

Answer:

$x=5+\frac{29}{z}-\frac{y}{z}$

$y=5z+29-xz$

Step-by-step explanation:

Given: $(4z^2+7z-8)(-z+3)=-4z^3+xz^2+yz-24$ ; find x and y.

Let's start with finding x first. Let's distribute the left side of the equation.

$-4z^3+5z^2+29z-24=-4z^3+xz^2+yz-24$

Let's move everything we can to the left side of the equation. Some things will cancel out.

$5z^2+29z=xz^2+yz$

Now, let's move the term that includes $x$ to the left side of the equation. Everything else should be moved to the right.

$-xz^2=-5z^2-29z+yz$

Let's get rid of the negative sign in front of $x$ by dividing both sides by -1.

$xz^2=5z^2+29z-yz$

To get $x$ completely isolated, divide both sides by $z^2$ .

$\frac{xz^2}{z^2}=\frac{5z^2}{z^2}+\frac{29z}{z^2}-\frac{yz}{z^2}$

Simplify.

$x=5+\frac{29}{z}-\frac{y}{z}$

Let's solve for y. We will start with the distributed and simplified equation to make it easier.

$5z^2+29z=xz^2+yz$

Now, let's move the term that includes $y$ to the left side of the equation. Everything else should be moved to the right.

$-yz=-5z^2-29z+xz^2$

Again, let's get rid of the negative sign in front of the $y$ by dividing both sides by -1.

$yz=5z^2+29z-xz^2$

To isolate y, divide both sides by z.

$\frac{yz}{z}=\frac{5z^2}{z}+\frac{29z}{z}-\frac{xz^2}{z}$

Simplify.

$y=5z+29-xz$

8 0

2 years ago

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