Answer:
Explanation:
A chemical reaction describes the reaction between reactants to produce products.
A chemical equation is represented as a reactant present on the left-hand side of the equation if two or more reactants are present they are separated by the "plus" sign.
On the right side of the equation product is written and if more than one product is formed then these are separated by "plus" sign as in the reactants.
The reactant and the products are separated by an arrow, the head of arrow is in the direction of the product when the reaction is irreversible.
In the case of reversible reactions or chemical reactions that are present in equilibrium, the reactant and product are separated by a double-headed arrow.
Answer:
im only 11 but By convention in standard cell notation, the anode is written on the left and the cathode is written on the right. So, in this cell: Zinc is the anode (solid zinc is oxidised). Silver is the cathode (silver ions are reduced).
Explanation:
Answer:
The amount of HC₂H3₃2(aq) in the flask after the addition of 5.0mL of NaOH(aq) compared to the amount of HC₂H₃O₂(aq) in the flask after the addition of 1.0mL is much smaller because more HC₂H₃O₂(aq) is required to react with 5.0 mL NaOH than with 1.0 mL NaOH.
Explanation:
Equation of the reaction between acetic acid, HC₂H₃O₂(aq) and sodium hydroxide, NaOH(aq) is given below:
CH₃COOH (aq) + NaOH (aq) ----> CH₃COONa (aq) + H₂O
The equation of the reaction shows that acetic acid andsodium hydroxide will react in a 1:1 ratio
Since the concentration of NaOH was not given, we can assume that the concentration is 0.01 M
Moles of NaOH in 5.0 mL of 0.01 M NaOH = 0.01 × 5/1000 = 0.00005 moles
Moles of NaOH in 1.0 mL of 0.01 M NaOH = 0.01 ×1/1000 = 0.0001 moles
Ratio of moles of NaOH in 5.0 mL to 1.0 mL = 0.00005/0.00001 = 5
There are five times more moles of NaOH in 5.0 mL than in 1.0 mL and this means that 5 times more the quantity of HC₂H₃O2(aq) required to react with 1.0 mL NaoH is needed to react with 5.0 mL NaOH.
Therefore, the amount of HC₂H₃O2(aq) in the flask after the addition of 5.0mL of NaOH(aq) compared to the amount of HC₂H₃O₂(aq) in the flask after the addition of 1.0mL is much smaller because more HC₂H₃O₂(aq) is required to react with 5.0 mL NaOH than with 1.0 mL NaOH.
Answer:
A. He sent a cathode ray between electrically charged metal plates
When non-metal atoms ionize they gain electrons.<span> Some examples of this are the halogen elements: F, Cl, Br and I, each, can gain one electron from the respective anions, F-, Cl-, Br-, and I-. O and S, may gain two electrons to form the anions O2- and S2-. This is due to the fact that those elements only need one (in the case of the halogens) or two (in the case of O and S) electrons to reach the most stable configuration of the closest noble gas (with the last shell of electrons full), so they are ready to gain those electrons and form the corresponding ions.</span>
