All categories

2 years ago

Which aqueous solution has the highest boiling point?

Chemistry

1 answer:

MissTica2 years ago

7 0

Answer:

All three solutions have the same boiling point.

Explanation:

Elevation in boiling point is a colligative property. A colligative property depends upon the number of solute molecules irrespective of nature or molecular weight etc.

As all the given solutes (in all the three solutions) are non ionic (will not dissociate into ions) so with same molality (moles per unit Kg) they will have same number of molecules. And thus all the three aqueous solutions will have same boiling point.

You might be interested in

The decay of which radioisotope can be used to estimate the age of the fossilized remains of an insect?

Dmitriy789 [7]

(4) C-14 Carbon is found in all living organisms.

3 0

2 years ago

Read 2 more answers

Which corresponds to a pressure of 1.23 atm??

Vadim26 [7]

Atmospheric pressure, sometimes also called barometric pressure, is the pressure exerted by the weight of air in the atmosphere of Earth (or that of another planet)

1 atm is equivalent to = 101325 Pa

= 760 mmHg

= 760 torr

= 1.01325 bar

So 1.23 atm is equal to

= 124629.8 Pa

= 934.8 mmHg

= 934.8 torr

= 1.2462 bar

6 0

2 years ago

According to Newton’s first law of motion, when will an object at rest begin to move?

Maurinko [17]

When it is acted upon by an outside force

8 0

2 years ago

Read 2 more answers

Which radioactive emission has the smallest (least) mass? Question options:

Tems11 [23]

Answer:

The answer is D. gamma rays

Explanation:

A radioactive atom can have three different types of emission:

alpha particles (α) = they have a mass of 4 amu and they have a very low penetrating power.

Beta particles (β) = they have 5x $10^{-4}$ amu and they have an intermediate penetrating power

Gamma rays (γ) = they are not particles basically just energy so its mass is ≈ 0 and its penetrating power is higher

For this reason Gamma emissions (γ) has the smallest mass value.

8 0

2 years ago

A cubic piece of platinum metal (specific heat capacity = 0.1256 J/°C･g) at 200.0°C is dropped into 1.00 L of deuterium oxide ('

polet [3.4K]

Answer:

$a=5.65cm$

Explanation:

Hello,

In this case, for this heat transfer process in which the heat lost by the hot platinum is gained by the cold deuterium oxide based on the equation:

$Q_{Pt}=-Q_{Deu}$

We can represent the heats in terms of mass, heat capacities and temperatures:

$m_{Pt}Cp_{Pt}(T_f-T_{Pt})=-m_{Deu}Cp_{Deu}(T_f-T_{Deu})$

Thus, we solve for the mass of platinum:

$m_{Pt}=\frac{-m_{Deu}Cp_{Deu}(T_f-T_{Deu})}{Cp_{Pt}(T_f-T_{Pt})} \\\\m_{Pt}=\frac{-1.00L*1110g/L*4.211J/(g\°C)*(41.9-25.5)\°C}{0.1256J/(g\°C)*(41.9-200.0)\°C} \\\\m_{Pt}=3860.4g$

Next, by using the density of platinum we compute the volume:

$V_{Pt}=\frac{3860.4g}{21.45g/cm^3}\\ \\V_{Pt}=180cm^3$

Which computed in terms of the edge length is:

$V=a^3$

Therefore, the edge length turns out:

$a=\sqrt[3]{180cm^3}\\ \\a=5.65cm$

Best regards.

6 0

2 years ago