Answer:
The first one is wrong, they don’t push nor pull, it’s an invisible force that acts on everything equally
Explanation:
Hopes this helps
Answer:
Explanation:
If M be mass of moon and m be mass of spacecraft
potential energy of moon -spacecraft system
= - G M m / R where R is radius of orbit of spacecraft
kinetic energy of spacecraft in the orbit
= 1/2 m v² = GMm / 2R
Total energy of spacecraft
= GMm / 2R - G M m / R
= - GMm / 2R
for spacecraft to leave the orbit, energy required
= GMm / 2R
= 6.67259 x 10⁻¹¹ x 7.36 x 10²² x 14800 / (2 x 1.79877 x 10⁶)
= 202035.8 x 10⁵ J .
Answer:
(a) 49.0 mm
Explanation:
#First we need to calculate the height of the mercury arm:
Reduced pressure is 715.7torr, Initial Pressure is 797.3torr, Required pressure is:
The difference in the two arms will give the pressure difference between the gas placed in the flask attached to an open-end mercury manometer.
Hence the height of the mercury in the arm is 49.00mm
Answer:
The acceleration of the car, a = 60 m/s²
Explanation:
Given data,
The initial velocity of the car, u = 0 m/s
The final velocity of the car, v = 30 m/s
The displacement of the car, s = 0.25 km
Using the III equations of motion
v² = u² + 2as
a = (v² - u²) / 2s
= 30 / 2 x 0.25
= 60 m/s²
Hence, the acceleration of the car, a = 60 m/s²
